Blog Log in Get Started Free

NEET Practice Questions (MCQs) with Answers & Solutions

Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology

● ● ● ● ●

Mendius method of preparation of amines consists of:

catalytic reduction of alkyl cyanides

reduction of amide with LiAlH₄

reduction of nitroparaffin with Sn + HCl

reduction of oximes with Na + C₂H₅OH

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

(a) $R - CN \overset{Reduction}{\to} R {CH}_{2} {CH}_{2}$

● ● ● ● ●

The correct order of basicities of the following compounds is:

$\underset{1}{{CH}_{3} - {C_{| |}^{| |}}_{{NH}_{2}}^{NH}}, \underset{2}{C H_{3} C H_{2} N H_{2}}, \underset{3}{{(C H_{3})}_{2} N H}, \underset{4}{C H_{3} - \overset{O}{\overset{| |}{C}} - N H_{2}}$

2 > 1 > 3 > 4

1> 3 > 2 > 4

3 > 1 > 2 > 4

1 > 2 > 3 > 4

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Negative charge developed on N in the resonance hybride makes it more basic as it loses electron pair readily. Also $2 °$ amine is more basic than $1 °$ amine due to +ve IE of alkyl group. In amide, the lone pair remains less avaible due to delocalisation is resonance.

● ● ● ● ●

A primary amine heated with CS₂ in presence of excess of HgCl₂ gives isothiocyanate. The reaction is called:

Hofmann's bromamide reaction

Hofmann's mustard oil reaction

Perkin's condensation

Hofmann's elimination

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

The reaction of a primary amine with carbon disulfide (CSâ‚‚) in the presence of excess mercuric chloride (HgClâ‚‚) to form an isothiocyanate is known as the Hofmann's mustard oil reaction. This reaction is used to synthesize isothiocyanates, which have a characteristic pungent odor.

● ● ● ● ●

Reaction of cyclohexanone with dimethylamine in the presence of catalytic amount of an acid forms a compound if water during the reaction is continuously removed. The compound formed is generally known as:

Schiff's base

an enamine

an imine

an amine

You've reached today's free limit of 20 questions. Log in to keep practising for free.

● ● ● ● ●

Biuret test is not given by:

proteins

carbohydrates

polypeptides

urea

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

The Biuret test is a chemical test used to detect the presence of peptide bonds in proteins and polypeptides. It involves treating the sample with a copper(II) salt solution and observing a violet or pink color change. Carbohydrates do not contain peptide bonds, so they do not give a positive Biuret test.

● ● ● ● ●

An aromatic amine (A) was treated with alcoholic potash and another compound (Y) when a foul smelling gas was formed with formula C₆H₅NC. (Y) was formed by reacting a compound (Z) with Cl₂ in the presence of slaked lime. Compound (Z) is:

$C_{6} H_{5} {NH}_{2}$

${CH}_{3} OH$

${CH}_{3} {COCH}_{3}$

${CHCl}_{3}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$C_{6} H_{5} {NH}_{2} + KOH (Y) \to C_{6} H_{5} NC;$ (Y) is CHCl₃; (Y) is formed from (Z) + Cl₂ + Ca(OH)₂and thus (Z) is CH₃COCH₃.

● ● ● ● ●

Aniline was acetylated. The product on nitration followed by alkaline hydrolysis gave:

o-nitroacetanilide

o- and p-nitroaniline

m-nitroaniline

acetanilide

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Aniline, when acetylated, forms acetanilide. Nitration of acetanilide gives a mixture of o-nitroacetanilide and p-nitroacetanilide. Alkaline hydrolysis of these compounds removes the acetyl group, giving a mixture of o-nitroaniline and p-nitroaniline.

● ● ● ● ●

Pyridine possesses :

aromatic nature

unsaturated aliphatic nature

alicyclic nature

aliphatic nature

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Pyridine is an aromatic heterocyclic compound consisting of a six-membered ring with five carbon atoms and one nitrogen atom. The presence of the delocalized Ï€-electron system in the ring gives pyridine its aromatic nature, similar to benzene.

● ● ● ● ●

Ammoniacal solution of Ni(CN)₂ reacts with C₆H₆ to produce a light violet coloured crystaline compound of the formula:

$Ni (CN)_{2} \cdot C_{6} H_{5}$

$C_{6} H_{5} {CH}_{3}$

$Ni (CN)_{2} C_{6} H_{6}$

$Ni (CN)_{2} {NH}_{3 \cdot} C_{6} H_{6}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

● ● ● ● ●

The reaction, $C_{6} H_{5} N_{2} Cl \overset{{Cu}_{2} {Cl}_{2} / HCl}{\to} C_{6} H_{5} Cl + N_{2}$ is called:

Etard's reaction

Sandmeyer's reaction

Wurtz-Fitting reaction

Perkin's reaction

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

(b) Replacement of N₂Cl by halogen atom of CuX-HX from benzene diazonium chloride is called Sandmeyer's reaction.

Ready to ace NEET?

Free access · No credit card required

Browse All Questions Create Free Account

Frequently Asked Questions

Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.