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NEET NEET Questions — Free MCQ Practice

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Hinsberg's method to separate amines is based on the use of:

A.

benzene sulphonyl chloride

B.

benzene sulphonic acid

C.

ethyl oxalate

D.

acetyl chloride

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Explanation

(a)

Amines serve as nucleophiles in attacking the sulfonyl chloride electrophile, displacing chloride. The sulfonamides resulting from primary and secondary amines are poorly soluble and precipitate as solids from solution:

PhSO₂Cl + 2 RR'NH → PhSO₂NRR' + [RR'NH₂⁺]Cl⁻

For primary amines (R' = H), the initially formed sulfonamide is deprotonated by base to give water-soluble sulfonamide salt (Na[PhSO₂NR]):

PhSO₂N(H)R + NaOH → Na⁺[PhSO₂NR⁻] + H₂O

Tertiary amines promote hydrolysis of the sulfonyl chloride functional group, which affords water-soluble sulfonate salts.

PhSO₂Cl + R₃N + H₂O → R₃NH⁺[PhSO₃⁻

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An amine reacts with $C_{6} H_{5} {SO}_{2} Cl$ and the product is soluble in alkali, amine is:

A.

$1 °$

B.

$2 °$

C.

$3 °$

D.

all of these

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Explanation

(a) $R {NH}_{2} + C_{6} H_{5} {SO}_{2} Cl \overset{}{\to} C_{6} H_{5} {SO}_{2} NH R$

(Sulphonamide

soluble in alkali)

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When $({NH}_{4})_{2} {SO}_{4} + KCNO are heated, we get :$

A.

nitrogen

B.

carbon dioxide

C.

biuret

D.

amminium carbonate

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Explanation

(c) ${NH}_{4} CNO \overset{∆}{\to} {NH}_{2} {CONH}_{2} \overset{}{\to} {NH}_{2} {CONHCONH}_{2}$

Urea Biuret

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Mark the correct statement:

A.

Methylamine is slightly acidic

B.

Methylamine is less basic than ammonia

C.

Methylamine ia a stronger base than ammonia

D.

Methylamine forms salts with alkalies

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Explanation

Methylamine (CH₃NH₂) is a stronger base than ammonia (NH₃) due to the electron-donating effect of the methyl group. The methyl group increases the electron density on the nitrogen atom, making it more basic compared to ammonia.

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A colourless organic compound gave brisk effervescence with a mixture of NaNO₂ and dil.HCl. It could be:

A.

glucose

B.

oxalic acid

C.

urea

D.

benzoic acid

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Explanation

Urea (CO(NH₂)₂) is the correct answer. When urea is treated with a mixture of sodium nitrite (NaNO₂) and dilute hydrochloric acid (HCl), it undergoes a reaction that generates nitrogen gas, causing brisk effervescence.

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Aliphatic amines are soluble in water because:

A.

they are basic

B.

they are amino compounds

C.

they are lighter than water

D.

of formation of hydrogen bonds with water

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Explanation

Aliphatic amines are soluble in water because of their ability to form hydrogen bonds with water molecules. The nitrogen atom in amines has a lone pair of electrons, which can form hydrogen bonds with the hydrogen atoms of water molecules.

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Which of the following reagents will convert nitromethane into methylamine ?

A.

Zn/HCl

B.

Zn/NaOH

C.

Zn/C₂H₅OH

D.

Ni/H₂

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Explanation

${CH}_{3} {NO}_{2} \to_{or Sn / HCl}^{Zn / HCl} {CH}_{3} {NH}_{2}$

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Nitrobenze on reduction with Al-Hg and water gives:

A.

azobenze

B.

aniline

C.

azoxy benzene

D.

phenylhydroxylamine

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Explanation

(d) $C_{6} H_{5} {NO}_{2} \to_{Neutral med .}^{Al - Hg / water} C_{6} H_{5} NHOH$

Phenylhydroxylamine

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The reduction of CH₃CN to CH₃CH₂NH₂ is called:

A.

Rosenmund's reduction

B.

Clemmensen's reduction

C.

Mendius reduction

D.

Hofmann's reduction

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Explanation

(c) The conversion of -CN to -CH₂NH₂ by catalytic reduction is called Mendius reaction.

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Aniline and ethylamine resembles in:

A.

solubility

B.

action with HNO₂

C.

action of Grignard reagent

D.

coupling reaction

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Explanation

(c) Both gives alkane (RH) with Grignard reagents RMgX due to the presence of acidic hydrogen (N-H).

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