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Consider a rigid body where all forces acting on it are coplanar. How many independent conditions are required for its mechanical equilibrium?

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Explanation

The NCERT text states: 'In a number of problems all the forces acting on the body are coplanar. Then we need only three conditions to be satisfied for mechanical equilibrium. Two of these conditions correspond to translational equilibrium... The third condition corresponds to rotational equilibrium.'

For a particle, which of the following conditions apply for its equilibrium?

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Explanation

The text clearly states: 'Since consideration of rotational motion does not apply to a particle, only the conditions for translational equilibrium (Eq. 6.30 a) apply to a particle. Thus, for equilibrium of a particle the vector sum of all the forces on it must be zero.'

What is the key characteristic of equilibrium under concurrent forces, as discussed for a particle?

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Explanation

The NCERT text mentions: 'Thus, for equilibrium of a particle the vector sum of all the forces on it must be zero. Since all these forces act on the single particle, they must be concurrent. Equilibrium under concurrent forces was discussed in the earlier chapters.'

A body is in partial equilibrium if it is in:

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Explanation

The text defines partial equilibrium: 'A body may be in partial equilibrium, i.e., it may be in translational equilibrium and not in rotational equilibrium, or it may be in rotational equilibrium and not in translational equilibrium.'

A light rod (AB) has two parallel forces, equal in magnitude and acting in the same direction, applied perpendicular to its ends A and B. Which statement accurately describes its state of equilibrium?

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Explanation

Referring to Fig. 6.20(a) and its description: 'The moment of the forces at A and B will both be equal in magnitude (aF), but opposite in sense...The net moment on the rod will be zero. The system will be in rotational equilibrium, but it will not be in translational equilibrium; $\sum F \neq 0$.'

If the total force on a rigid body is zero, what can be inferred about its linear momentum?

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Explanation

The NCERT text states: 'If the total force on the body is zero, then the total linear momentum of the body does not change with time. Eq. (6.30a) gives the condition for the translational equilibrium of the body.'

If the translational equilibrium condition holds for a rigid body, what can be said about the rotational equilibrium condition [Eq. 6.30(b)] concerning the choice of origin?

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Explanation

The text explains: 'One can show that if the translational equilibrium condition [Eq. 6.30(a)] holds for a rigid body, then such a shift of origin does not matter, i.e. the rotational equilibrium condition is independent of the location of the origin about which the torques are taken.'

Equations for mechanical equilibrium, $\sum \vec{F_i} = 0$ and $\sum \vec{\tau_i} = 0$, are vector equations. How many scalar equations do they represent in total for a general rigid body?

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Explanation

The NCERT text clarifies: 'Eq. (6.30a) and Eq. (6.30b), both, are vector equations. They are equivalent to three scalar equations each. Eq. (6.30a) corresponds to $\sum F_{ix} = 0$, $\sum F_{iy} = 0$ and $\sum F_{iz} = 0$. Similarly, Eq. (6.30b) is equivalent to three scalar equations $\sum \tau_{ix} = 0$, $\sum \tau_{iy} = 0$ and $\sum \tau_{iz} = 0$.'

What happens to the rotational state of motion of a rigid body if the total torque on the body does not vanish?

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Explanation

The text states: 'The total torque on the body may not vanish. Such a torque changes the rotational state of motion of the rigid body, i.e. it changes the total angular momentum of the body in accordance with Eq. (6.28 b).'

When considering the equilibrium of a rigid body, the term 'force' refers to:

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Explanation

The NCERT text explicitly states: 'Henceforth we shall omit the adjective 'external' because unless stated otherwise, we shall deal with only external forces and torques.'

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