Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
A fall in GFR triggers the release of which substance from JG cells to restore normal GFR?
The NCERT text states, 'A fall in GFR can activate the JG cells to release renin which can stimulate the glomerular blood flow and thereby the GFR back to normal.'
Considering the daily filtrate volume of 180 litres and urine output of 1.5 litres, what percentage of the filtrate is reabsorbed?
The text states, 'A comparison of the volume of the filtrate formed per day (180 litres per day) with that of the urine released (1.5 litres), suggest that nearly 99 per cent of the filtrate has to be reabsorbed by the renal tubules.'
The driving force for glomerular filtration is:
The NCERT text states, 'Filtration is a non-selective process performed by the glomerulus using the glomerular capillary blood pressure.'
Which part of the nephron forms the outer, double-walled cup-like structure that encloses the glomerulus?
The text describes, 'The renal tubule starts with a double walled Bowman’s capsule and is further differentiated... The Bowman’s capsule encloses the glomerulus to form Malpighian or renal corpuscle.'
The afferent arteriole is involved in the formation of which part of the nephron responsible for filtration?
The provided information states, 'Glomerulus is a tuft of capillaries formed from afferent arterioles, fine branches of renal artery.'
Which term best describes the process of filtration performed by the glomerulus, where substances pass based on pressure rather than specific selection?
The NCERT text explicitly refers to filtration as a 'non-selective process performed by the glomerulus'.
Which of the following statements correctly describes the calculation of work done by a variable force in one dimension?
As per the NCERT text, 'if the displacements are allowed to approach zero, then the number of terms in the sum increases without limit, but the sum approaches a definite value equal to the area under the curve in Fig. 5.3(b). Then the work done is $W = \int_{x_i}^{x_f} F(x) dx$'. This integral represents the area under the force-displacement curve.
A woman pushes a trunk on a railway platform. She applies a force of 100 N over the first 10 m, and then her applied force reduces linearly to 50 N over the next 10 m. The frictional force opposing the motion is constant at 50 N. What is the total work done by the woman on the trunk over the entire 20 m displacement?
According to Example 5.5, the work done by the woman for the first 10 m (rectangle ABCD) is $100 \text{ N} \times 10 \text{ m} = 1000 \text{ J}$. For the next 10 m (trapezium CEID), the work done is $(1/2) \times (100 + 50) \text{ N} \times 10 \text{ m} = 750 \text{ J}$. The total work done by the woman is $1000 \text{ J} + 750 \text{ J} = 1750 \text{ J}$.
In the scenario described in the previous question (woman pushing a trunk), what is the work done by the frictional force over the total 20 m displacement?
As per Example 5.5, the frictional force $f$ is constant at 50 N and opposes motion, hence it is negative. The work done by friction is $W_f = (-50 \text{ N}) \times 20 \text{ m} = -1000 \text{ J}$. The area on the negative side of the force axis has a negative sign.
For a variable force $F(x)$, if the displacement $\Delta x$ is small, the work done $\Delta W$ can be approximated as:
The NCERT text states: 'If the displacement $\Delta x$ is small, we can take the force $F(x)$ as approximately constant and the work done is then $\Delta W = F(x) \Delta x$.'
Ready to ace NEET?
Free access · No credit card required
Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.
No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.
The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.