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If $x = 5\sin\left(\pi t + \dfrac{\pi}{3}\right)$ m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are:
Amplitude 5 m; $T = 2\pi/\pi = 2$ s.
A thermodynamic system is taken through the cycle $abcda$. The work done by the gas along the path $bc$ is:
$bc$ is isochoric ($V$ constant), so $W = \int P\,dV = 0$.
${}^{290}_{82}X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrightarrow{e^{-}} Q$. In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are:
$Q = (286, 81)$ after $\alpha$, $\beta^+$, $\beta^-$, $\beta^-$.
Two bodies A and B of same mass undergo completely inelastic one dimensional collision. The body A moves with velocity $v_1$ while body B is at rest before collision. The velocity of the system after collision is $v_2$. The ratio $v_1 : v_2$ is:
$mv_1 = 2m v_2 \Rightarrow v_1 : v_2 = 2 : 1$.
In the following circuit, the equivalent capacitance between terminal $A$ and terminal $B$ is:
Balanced bridge → middle $2\,\mu F$ carries no charge. Two arms each give $1\,\mu F$ in series; in parallel: $2\,\mu F$.
A horizontal force $10\ N$ is applied to a block $A$ as shown in figure. The mass of blocks $A$ and $B$ are 2 kg and 3 kg, respectively. The blocks slide over a frictionless surface. The force exerted by block $A$ on block $B$ is:
$a = 10/5 = 2$ m/s²; force on B $= 3 \times 2 = 6$ N.
A wheel of a bullock cart is rolling on a level road as shown in the figure below. If its linear speed is $v$ in the direction shown, which one of the following options is correct ($P$ and $Q$ are any highest and lowest points on the wheel, respectively)?
Pure rolling: top $2v$, contact 0.
The mass of a planet is $\dfrac{1}{10}$th that of the earth and its diameter is half that of the earth. The acceleration due to gravity on that planet is:
$g_p = (1/10)(2)^2 g_e = 0.4 \times 9.8 = 3.92$ m/s².
The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young's modulus, respectively, are $8\times 10^8\ \text{N m}^{-2}$ and $2\times 10^{11}\ \text{N m}^{-2}$, is:
$\Delta L = \sigma L/Y = 4\times 10^{-3}$ m $= 4$ mm.
If the monochromatic source in Young's double slit experiment is replaced by white light, then
Path difference 0 at the centre for all $\lambda$ → white fringe; coloured fringes either side.
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.