Major products A and B formed in the following reaction sequence are:
2-methyl-1-cyclohexanol (i.e. 1-methylcyclohexanol — OH and CH₃ on the same ring carbon)
$\xrightarrow{PBr_3}$ A (major) $\xrightarrow[\Delta]{alc.\ KOH}$ B (major)
PBr₃ replaces OH with Br at the same (tertiary) carbon → 1-bromo-1-methylcyclohexane. Alcoholic KOH gives E2 to the Saytzeff alkene → 1-methylcyclohexene.