When 2 Amp current is passed tarough a tangent galvanometer. It gives a deflection of $ 30 ^ \circ $ . For $ 60^ \circ $ deflaction, the current must be
$ I \;\alpha\; tan \phi $ $ { I_1 \over I_2 } = { tan \phi1 \over tan \phi 2 } $ $ { 2 \over I_2 } = { tan 30 ^\circ \over tan 60 ^\circ } $ $ I_2 = 6Amp $