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There are two wires of same material and same length. While the diameter of second wire is 2 times, the diameter of first wire. Then what will be the ratio of extension produced in the wire by applying same load ?
$ l = {FL \over AY} $ $ \therefore l \alpha { 1 \over r^2} $ ( F,L and Y are constant )
When the length of a wire having cross-section area $ 10 ^{-6} m^ 2 $ is stretched by 0.1% then tension in it is 100 N. Young's modulus of material of wire is...........
$ A = 10 ^ {-6} m^2 , Y = { {I \over A} \over { \triangle l \over l } } $
Two wires of equal lengths are made of the same material wire A has a diameter that is twice as that of wire B. If identical weights are suspended from the ends of these wires the increase in length is............
$ l = {FL \over AY } \Rightarrow l \alpha { 1 \over r^2} $ ( F,L and Y are constant)
Steel and copper wires of same length are stretched by the same weight one after the other. Young's modulus of steel the ratio increase in length ?
$ l = { FL \over AY} \Rightarrow { l_{steel} \over l_{a_1} } = { Ya_1 \over Y_{steel} } $ ( F,L and Y are constant )
A substance breaks down by a stress of If the density of the material of the wire is then the length of wire of the substance which will break under its own weight when suspended vertically is............
L = P /dg
If longitudinal strain for a wire is 0.03 and its poisson's ratio is 0.5, then what is its lateral strain ?
$ \sigma = { Lateral strain \over Longitutdinal Strain } $
An aluminium rod $ ( Young's modulus = 7 \times 10 ^ 9 N/m^2 ) $ has a breaking strain of 0.2 % what is the minimum cross-sectional area of the rod in order to support a load of $ 10^4 $ Newtons ?
$$ Y = { F /A \over strain } \Rightarrow A = { F \over Y_x Strain } $$
Two wires of copper having the length in the ratio 4 : 1 and their are as 1 : 4 are stretched by the same force. What will be the ratio of longitudinal strain in the two wires ?
$$ strain and stress \alpha { F \over A} $$
A wire elongates by 1 mm when a load W is hanged from it. If the wire goes ever a pulley and two weight W each are hang at the two ends. What will be the elongation of the wire ? (in mm)
Elongation in the wire l = TL /AY $ \therefore Elongation in wire tension in the wire in first case T_1 = wand in second case $ $ T_2 = { 2W \over W + W } = W $ As Tension in the wire in both the cases are equal. $ \therefore Elongation in the wire will be equal.$
200 kg weight hanged at a free edge of vertical wire of length 600.5 cm when removed the weight, length reduced by 0.5 cm and it gets original status then what is the young modulus of wire ?
Y = FA / Al
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.