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The ratio of diameter of two wires of same material is n : 1 the length of wires are 4 m each. On applying the same load. What will be the increase in length of their wire ?
$ l \alpha { F \over r^2 y } \Rightarrow l \alpha { 1 \over r^2 } $ ( F,Land Y are constant )
A steel wire is stretched with a definite load of If the young's modulus of the wire is Y. For decreasing the value of Y............
It is the specific property of a particular material at a given temperature which can be changed only by temperature variations.
The area of cross-section of a steel wire is $ ( Y = 2 \times 10^{11} N /m^2 ) $ is $ 0.1 cm^2 $ , what will be the force required to double its length ?
When the length of wire is doubled then l = L and strain = 1 $ \therefore Y = strain = F / A $
Two wires A & B are of same materials. Their lengths in the ratio 1 : 2 and diameters are in the ratio 2 : 1 when stretched by force $ F_A and F_B $ respectively, they get equal increase in lengths . Then the ratio $ { FA \over FB } $ should be ....
$ F = Y \times A \times {l \over L } \Rightarrow F \alpha { r^2 \over L } $ ( y and L are constant )
The mean distance between the atoms of iron is $ 3 \times 10 ^ {-10} $ and interatomic force constant for iron is 7 N /m . What is the young's modulus of elasticity for iron ?
$ Y = { r \over r_0} = { 7 \over 3 \times 10^{-10 } } $
A force of 200 N is applied at one end of a wire of length 2 m and having area of cross-section $ 10 ^ {-2} cm^2 $ , the other end of the wire is rigidly fixed. If of linear expansion of the wire $ \alpha = 8 \times 10 ^ {-6} / ^\circ C $ and young's modulus $ Y = 2.2 \times 10^{11} N/m^2 $ and its temperature is increased by $ 5 ^\circ C $ then the increase in the tension of the wire will be..........
$ Increase in tension of wire = YA \alpha \triangle Q $
A uniform plank of young's modulus Y is moved over a smooth horizontal surface by a constant horizontal force F, The area of cross-section of the plank is A. What is the compressive strain on its plank in the direction by the force ?
$ Y = { { F \over A } \over strain } \Rightarrow strain = { F \over AY } $
A rubber cord catapult has cross-sectional area $ 25 mm^2 $ and initial length of cord is 10 cm. It is stretched to 5 cm and then released to project a missile of mass 5 gm. Taking $ Y_{rubber} = 5 \times 10^8 N/m^2 $ velocity of projected missile is ..........
Potential energy stored in the rubber cord calapult will be covered into kinetic energy of mass $ {1 \over 2 } mv^2 = {1 \over 2} { YAL^2 \over L } $
A wire of cross-section $4 mm^2$ is stretched by 0.1 mm by a certain weight. How far (length) will be wire of same material and length but of area $8 mm^2$ stretched under the action of same force.
$ l = { FL \over AY } $ $ \therefore l \alpha { 1 \over A} $ ( F , L and Y are constant ) $ { l_2 \over l_1} = { A_1 \over A_2} = {4 \over 8} = {1 \over 2} \Rightarrow l_2 = { l_1 \over 2 } = { 0.1 \over 2 } = 0.05 mm $
According to Hooke's law of elasticity stress is increased the ratio of stress to i strain.........
$ Y = { stress \over strain } = constant $ It depends only on nature of material.
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.