Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Young's modulus of rubber is $ 10 ^ 4 N /m^2 $ and area of cross section is $ 2 cm^2 $ if force of $2 \times 10^5 dyne $ is applied along its length then its initial length L becomes .............
$ l = { FL \over AY } $ $ \therefore Final length = initial lengh + increament = 2L $
A copper wire of length 4 mand area of cross-section $1.2 cm^2$ is stretched with a force of $ 4.8 \times 10^3 N$ . If young's modulus for copper is $ 1.2 \times 10^{11} N/m^2 $ . What will be the length increase of the wire ?
$ l = { FL \over AY } $
A wire of length 2 m is made from $10cm^3$ of copper. A force F is applied so that its length increases by 2mm. Another wire of length 8 m is made from the same volume of copper. If the force F is applied to it, its length will increase by............
$ l = { FL \over Ay } = {FL^2 \over (AL) Y} = {FL^2 \over VY} $ $ \therefore l \alpha L^ 2 If the volume of wire remains constant. $
In steel the young's modulus and the strain at the breaking point are $ 2 \times 10^{11} N /m^2 $ and 0.15 respectively the stress at the breaking point for steel is therefore ...........
$ Breaking stress = Strain \times young's modulus $
Which of the following statement is correct
In accordance with Hook's law
The force required to stretch a steel wire of $1cm^2$ cross-section to 1.1 times its length would be $ ( Y = 2 \times 10^{11} N /m^2 ) $
$ F = A \times Y \times Strain $
Which one of the following quantities does not have unit of force per unit area..........
Because strain is a dimensionless and unitless quantity.
A copper wire and a steel wire of same diameter and length are connected end to end a force is applied, which stretches their combined length by 1 cm, the two wires will have.......
stress = force /area In the present case, force applied and area of cross-section of wires are same. Therefore stress has to be the same Strain = stress /Y Since, the young's modulus of steel wire is greater than the copper wire, therefore strain in case of steel wire is less than that of in case of copper wire
A steel ring of radius r and cross-section area 'A' is fitted on to a wooden disc of radius R(R > r ) If young's modulus be E then what is force with which the steel ring is expanded ?
Knowledge base
A wire of diameter 1 mm breaks under a tension of 100 N. Another wire of same material as that of the first one, but of diameter 2 mm breaks under a tension of.........
$ Breaking force \alpha r^ 2$ If diameter becomes double then breaking force will become four times $ i.e 1000 \times 4 = 4000 N $
Ready to ace NEET?
Free access · No credit card required
Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.
No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.
The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.