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NEET Practice Questions (MCQs) with Answers & Solutions

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In the reaction $N_2O_{4(g)} \rightarrow 2NO_{2(g)} the pressure of N_2O_4 falls from 0.5 atm to 0.32 atm is 30 minutes, the rate of appearance of NO_{2(g)} $ is

A. $ 0.012 atm min ^ {-1} $ B. $ 0.024 atm min ^ {-1} $ C. $ 0.006 atm min ^ {-1} $ D. $ 0.003 atm min ^ {-1} $

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Explanation

$ 0.012 atm min^{-1} $ $ - { d [N_2 O_4 \over dt } = + { 1 \over 2 } { d [NO_2 ] \over dt }$ $ - { (0.32 - 0.50 ) \over 30 } = 0.006 = { 1 \over 2} {d [NO_2 ] \over dt } $ $ \therefore { d [NO_2] \over dt } = 0.012 atm min^ {-1} $

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In the reaction $K_1 and K_2$ are the velocity constants for the forward and backward reaction respectively. The equilibrium constant is

A. $ K = { K_1 \over K_2 } $ B. $ K = K_1 \times K_2 $ C. $ K = { K_2 \over K_1 } $ D. None of these

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Explanation

$ K = K_1 / K_2 $

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For the reaction A + B + C --> Products, Rate = $ K[A]^{1/2 } [B]^{1/3} [C]$ . The order of reaction is

A. 3 B. 1 C. 5/6 D. 11/6

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Explanation

$ { 1 \over 6 } Rate = k [A] ^ {1/2} [A]^{1/3} [c] ^1 $ $ \therefore Order of reaction = { 1 \over 2 } + { 1 \over 3} + { 1 \over 1 } = { 11 \over 6 } $

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$ A + 2B ---> C + D $ For a reaction from following data correct rat law = Mole
(A) 1 0.1 2 0.3 3 0.3 4 0.4 $ liter ^ {-1} $ (B) 0.1 0.2 0.4 0.1 mole lite-1 min-1 $ 6.0 \times 10^{-3} $ $ 7.2 \times 10^{-2} $ $ 2.88 \times 10^{-1} $ $ 2.4 \times 10^{-2} $

A. $ Rate = K [A]^2 [B] $ B. $ Rate = K [A]^2[B]^2$ C. $ Rate = K [A][B]^ 2 $ D. Rate = K [A][B]

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Explanation

$ Rate = K[A][B]^2 $ Keeping [B] constant, [A] is made a 4 times, rate also become 4 times. Hence rate $ \alpha [A] $ Keeping [A] constant, [B] is doubled, rate becomes 4 times. Hence rate $ \alpha [B] ^ 2$ $ \therefore rate = K[A][B]^ 2$

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In the reaction $ A + B --> Products $ , the doubling of [A], increases the reaction rate to four times, but doubling of [B] has no effect on the reaction rate. The rate expression is â€¦.

A. $ Rate = K [A]^ 2$ B. Rate = K [A] C. $ Rate = K [A]^2[B]^2$ D. Rate = K [A][B]

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Explanation

$ Rate = K[A][B] ^ 2 $ Keeping [B] constant, [A] is made a 4 times, rate also become 4 times. Hence $ rate \alpha [A] $
Keeping [A] constant, [B] is doubled, rate becomes 4 times. Hence $ rate \alpha [B]^2 $ $ \therefore rate = K[A][B]^2$

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A zero order reaction is one whose rate is independent of â€¦.

A. Reaction vessel volume B. Concentration of reactants C. temperature D. pressure of light

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Explanation

concentration of reactants

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The rate constant of a reaction changes when ...

A. pressure is changed B. concentration of reactants changed C. temperature is changed D. a catalyst is added

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Explanation

temperature is changed

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Which of the following is a reaction of zero order ?

A. $ H_2 + Cl_2 \rightarrow 2HCl $ B. $ 2 N_2 O_5 \rightarrow 4 NO_2 + O_2 $ C. $ 2 HI \rightarrow H_2 + I_2 $ D. $ H_2 + Br_2 \rightarrow 2 HBr $

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Explanation

$ H_2 + Cl_2 \rightarrow 2 HCl $

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Which of the following is a reaction of fractional order ?

A. $ 2 N_2 O_5 \rightarrow 4 NO_2 + O_2 $ B. $ 2NO_2 + F_2 \rightarrow 2 NO_2 F $ C. $ H_2 + Br_2 \rightarrow 2 HBr $ D. $ 2 NO + O_2 \rightarrow 2 NO_2 $

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Explanation

$ H_2 + Br_2 \rightarrow 2 HBr $

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A reaction involving two different reactants can never be a â€¦.

A. bimolecular reaction B. Unimolecular reaction C. first order reaction D. second order reaction

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Explanation

Unimolecular reaction

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