For a reaction $ 3A \Psi $ Products, the order of reaction
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
any value between 1 and 3
NEET Practice Questions (MCQs) with Answers & Solutions
Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
The rate determining step in a reaction is $ A + 2B --> C $ . Doubling the concentration of B would make the reaction rate...
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
$ four times \therefore rate a [B] ^ 2 $
The rate law of a reaction is $ rate = K [A]^ 2[B] $ . On doubling the concentration of both A and B the rate X will become ...
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
$ 8 x V_1 = k [A]^2 [B] = x V_2 = k [2A]^2 [2B] $ $ \therefore V_2 = 8x $
For the reaction $ CH_3COCH_3 + I_2 + H^+ --> Products $ , the rate is governed by, $ rate = K[CH_3COCH_3] [H^+]$ . The rate order of iodine is = _.
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
$ OO \therefore No I_2 $ in the rate law equation.
If the order of reaction is zero. It means that
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
rate of zero order reaction is independent of the concentration of the reacting species
The reactions of higher order are rare because
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
many body collisions have a low probability
$ 2A +2B ---> D + E $ For the reaction following mechanism has been proposed. $A + 2B --> 2C +D (slow) $ $ A + 2C --> E (Fast) $ The rate law expression for the reaction is
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
$ rate = K [A][B]^2$ Rate of reaction for slowest step
$ A2 + B2 ---> 2 AB $ reaction follow the mechanism as given below (i) $ A_2 --> 2A (fast) $ (ii) $ A + B_2 --> AB + B (slow) $ (iii) $ A + B ---> AB (fast) $ the order of overall reaction is
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
$ 1.5 From slowest step rate = k [B_2] [A] $ $ From 1 ^ {st} eq . Keq = [A] { 2 / [ A_2] } $ $ \therefore [A] = keq ^ {1 /2} . [A_2 ] ^ { 1 /2 } $ $ rate = K [B_2] keq ^ {1/2} . [A_2] ^ {1/2} = k .keq ^ {1/2} [A_2] ^ { 1 /2 } [ B_2 ] = K^1 [A_2 ]^ {1 /2 } [B_2 ] $
For the reaction $ 2A + B ---> Products $ , reaction rate = $ K [A][B]^ 2$ . Concentration of A is doubled and that of B is halved the rate of reaction will be ...
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
$ halved\; rate ' = k [A] [B] ^ 2 rate ' = k [2A] [{B \over 1}] ^ 2 $ $ = { 1 \over 2 } k [A] [B] ^ 2 $ $ \therefore x" = { 1 \over 2 } x ' $
In one reaction concentration of reaction A is increased by 16 times, the rate increases only two times. The order of the reaction would be ...
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
$ { 1 /4 } ( 1) r = k [A] ^ n (2) 2 r = k [16 A] ^ n $ $ 2r = K [A]^n 16 ^ n $ $ { 2r \over r } = { K [A] ^ n 6 ^ n \over K [A] ^ n } \therefore 2 = 16 ^ n \therefore n = { 1 \over 4} $
Ready to ace NEET?
Free access · No credit card required
Frequently Asked Questions
Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.
No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.
The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.