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X M NaCl is isotonic with fluids present in RBC (Red Blood Corpusceles), then what would be the value of x ? (M.w. Of NaCl =58.5 gm/mole) (Assume that ionic solid substances completely dissociates in the solution)
Which of the following solution is hypotonic in comparison with the solution of 0.4 M glucose?
Which of the following solution is hypotonic in comparison with 0.15 M kCl solution ?(Assume that ionic solid substances completely dissociates in the solution)
The question is asking which solution is hypotonic (lower osmotic pressure) compared to 0.15 M KCl solution. Urea is a non-electrolyte and does not dissociate into ions, so its osmotic pressure is solely due to the number of particles present. 0.2 M urea solution will have a lower osmotic pressure than 0.15 M KCl solution, which dissociates into ions.
Which of the following solution is isotonic with fluid of RBC ? (For NaCl, i=2)
Which of the following solution is isotonic with fluid of RBC ? (For NaCl, 2=2)
The fluid inside RBCs is isotonic with 0.9% w/v NaCl solution. Since glucose is a non-electrolyte, 2.02% w/v glucose solution will have the same osmotic pressure as 0.9% w/v NaCl solution, making it isotonic with the RBC fluid.
In Which of the following solution, RBC get burst ? $ (Molecular wt, CaCl_2=111, FeCl_3=162.5, glucose=180 and urea=60 gm/mole)$ (Assume that ionic solid completely dissociates in aqueous solution)
In Which of the following solution, RBC get shrinks ?$ (Molecular wt, CaCl_2=111, FeCl_3=162.5, glucose=180 and urea=60 gm/mole)$ (Assume that ionic solid completely dissociates in aqueous solution)
$ FeCl_3 ionizes 80 \% in their aqueous solution, then what will be the value of Vant ‘Hoff factor i? $
The van 't Hoff factor (i) represents the number of particles each molecule dissociates into in solution. If FeCl3 ionizes 80% into Fe3+ and 3Cl- ions, the average number of particles per molecule is 1 + 0.8(3) = 3.4, so the van 't Hoff factor is 3.4.
A substances associates in their solution as dimer (or bimolecule), then what will be the value of Van’t hoff factor i ?
$ When association of any substance takes place in a solution then degree of association is \leq 1 $ $ \therefore 0 \lt { i-1 \over {1 \over n } - 1 } \leq 1 $ $ \therefore 0 \lt { 1- I \over 1 - { 1 \over n} } \leq 1 $ $ \therefore 0 \lt 1 -I \leq 1 - { 1 \over n} $ $ \therefore - 1 \lt - i \leq - { 1 \over n } $ $ \therefore 1 \gt i \geq { 1 \over n } $ Here n = 2 ( given ) $ \therefore 1 \gt i \geq { 1 \over 2 } means 0.5 \leq i \lt 1 $
The solute remains as dimer in the m-molal solution; then elevation in boiling point irrelevant with the solution is -
For association ( given) n = 2 $ \therefore I \geq { 1 \over 2 }$ $ \therefore imKf \geq { mKf \over 2 } $ $ \therefore \triangle Tf \geq { mKf \over 2 } $
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