NEET Practice Questions (MCQs) with Answers & Solutions

The de-Broglie relationship relates the wavelength (λ) of a particle with its momentum (p) as λ = h/p, where h is the Planck's constant. By substituting p = mv, we get λ = h/mv, which is the correct expression relating wavelength, mass, and velocity of a particle.

Radius of Bohr orbit $ = { n ^ 2 \over Z } \times a_0 $

$ for Balmer series n_1 = 2 and n_2 = 3 for first line $

The principal quantum number (n) determines the energy level, and higher values of n correspond to higher energy levels. The orbital angular momentum quantum number (l) can have values from 0 to n-1. The magnetic quantum number (m) can have values from -l to +l. The spin quantum number (s) can have values of +1/2 or -1/2.

According to Bohr's theory, the energy of an electron in a hydrogen atom is given by E = -13.6 eV/n^2, where n is the principal quantum number. The energy difference between n=6 and n=8 is less than the energy difference between n=5 and n=7, as the energy levels get closer together for higher values of n.

The de Broglie wavelength of a particle is given by λ = h / (mv), where h is Planck's constant, m is the mass of the particle, and v is its velocity. For an electron with kinetic energy of 2.14 × 10^-22 J, we can calculate its velocity using the relation KE = (1/2)mv^2. Substituting the values, we get λ = 9.28 × 10^-8 m.