NEET Practice Questions (MCQs) with Answers & Solutions

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What will be de-Broglie wavelength of an electron moving with a velocity of $ 1·20 \times 10^5ms^{–1} $ ?

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The de-Broglie wavelength associated with ball of mass 200 g and moving at a speed of 5 m hour–1 is of the order of $(h = 6·625 \times 10^{–34} Js) $

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The third line of the Balmer series. in the emission spectrum of the hydrogen atom, is due to the transition from the

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Explanation

The Balmer series in the hydrogen spectrum corresponds to the electron transitions from higher energy levels to the second energy level (n=2). The third line in the Balmer series is due to the transition from the fifth orbit (n=5) to the second orbit (n=2).

The highest number of unpaired electrons are w present in

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Rutherford’s atomic model suggests the existence

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Explanation

Rutherford's alpha particle scattering experiment led to the discovery of the atomic nucleus. His model proposed that the positive charge and most of the mass of an atom is concentrated in a tiny region called the nucleus, surrounded by empty space with orbiting electrons.

Which is not true with respect to cathode rays?

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Explanation

Cathode rays are a stream of electrons emitted from the cathode of a vacuum tube. They are charged particles that can be deflected by electric or magnetic fields. However, they do not move with the speed of light, which is the maximum possible speed in the universe.

In hydrogen atom, energy of first excited state is -3·4 eV. Find out the K.E. of the same orbit of hydrogen atom

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Explanation

K.E. of e- in nth orbit = - $E_n$ = 3.4 e.V

The energy of the first electron in helium will be

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Explanation

$ E_n = - { 13.6 \over n^2 } Z^2 e.V $

In the Bohr’s orbit, what is the ratio of total kinetic energy and total energy of the electron

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Explanation

$ K.E = { 1 \over 2 } mv ^2 P.E = - { Ze^2 \over r } $ Electrostatic force = centrifugal force $ { Ze^2 \over r^2 } = {mv^2 \over r } \therefore P.E = -mv^2 $ $ Total energy = K.E + P.E = { 1 \over 2 } mv^2 - mv^2 = -{ 1 \over 2 }mv^2 \therefore { K.E \over Total Energy } = -1 $

In Bohr series of lines of hydrogen spectrum, the third line from the red end corresponds to which one of the following inter-orbit jumps of the electron for Bohr orbits in an atom of hydrogen ?

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