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Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 and 50 dyne/cm respectively Ratio of heights of liquids in the two tubes h1h2 is

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Explanation

(d) Ascent formula h=2Tcosθrdg

h1h2=T1T2×d2d1                   (r, θ and g are constants)

=6050×0.60.8=910 

Water rises in a vertical capillary tube upto a height of 2.0 cm . If the tube is inclined at an angle of 60° with the vertical, then upto what length the water will rise in the tube ?

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Explanation

(b) l=hcosθ=2cos60°= 4.0 cm

The surface tension for pure water in a capillary tube experiment is

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Explanation

(d) T=rhdg2cosθ . For pure water θ=0°   so T=rhdg2

Kerosene oil rises up the wick in a lantern

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Explanation

(a) Kerosene oil rises up the wick in a lantern due to the surface tension of the oil.

Water rises against gravity in a capillary tube when its one end is dipped into water because

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Explanation

(a) 

A capillary tube of radius R is immersed in water and water rises in it to a height H. Mass of water in the capillary tube is M. If the radius of the tube is doubled, mass of water that will rise in the capillary tube will now be

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Explanation

(b)

Initial mass of liquid in the tube,M=πR2H×ρWhen radius is doubled,As height of liquid α 1radiusFinal height of liquid  = H2Final mass of liquid=π(2R)2H2×ρ=2M

 

There is a horizontal film of soap solution. On it, a thread is placed in the form of a loop. The film is pierced inside the loop and the thread becomes a circular loop of radius R. If the surface tension of the loop be T, then what will be the tension in the thread ?

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A large number of water drops each of radius r combine to have a drop of radius R. If the surface tension is T and the mechanical equivalent of heat is J, then the rise in temperature will be

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Explanation

Volume of n small drops = Volume of large drop.   n43πr3 = 43πR3      nr3=R3Change in surface area        A=n4πr2-4πR2        =4πnr2-R2Reduction in surface energy =  T·A                                                   =T4πnr2-R2                                                   =T4πR3r-R2                                                    =T4πR31r-1RHeat  Q=WJ=T·4πR3J1r-1RQ=msTT·4πR3J1r-1R=1×43πR3×1×T          T=3TJ1r-1R

One kilogram of ice at 0°C is mixed with one kilogram of water at 80°C. The final temperature of the mixture is (Take: Specific heat of water = 4200 J kg-1k-1, Latent heat of ice = 336 kJ kg-1)

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The fastest mode of heat transfer is 

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Explanation

 In radiation, heat is transferred by electromagnetic waves, which have the fastest speed, so it is the fastest mode of heat transmission.

 

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