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If the surface tension of water is 0.06 ${Nm}^{- 1}$ , then the capillary rise in a tube of diameter 1 mm is ( $θ$ =0° )

1.22 cm

2.44 cm

3.12 cm

3.86 cm

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Explanation

(b) $h = \frac{2 T}{rdg} = \frac{2 \times 6 \times 10^{- 2}}{5 \times 10^{- 4} \times 10^{3} \times 10} = 2.4 \times 10^{- 2} m = 2.4 cm$

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A capillary tube when immersed vertically in liquid records a rise of 3 cm. If the tube is immersed in the liquid at an angle of $60 °$ with the vertical. The length of the liquid column along the tube is

9cm

6cm

3cm

2cm

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The action of a nib split at the top is explained by

Gravity flow

Diffusion of fluid

Capillary action

Osmosis of liquid

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Explanation

(c) The tip of nib of a writing pen is split to provide the capillary action. Due to capillary, ink will rise in the split of nib and allows the pen to write continuously.

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The correct relation is

$r = \frac{2 Tcosθ}{hdg}$

$r = \frac{hdg}{2 Tcosθ}$

$r = \frac{2 Tdgh}{cosθ}$

$r = \frac{Tcosθ}{2 hdg}$

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Explanation

(a) $r = \frac{2 Tcosθ}{hdg}$

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During capillary rise of a liquid in a capillary tube, the surface of contact that remains constant is of

Glass and liquid

Air and glass

Air and liquid

All of these

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Explanation

(c)

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A shell having a hole of radius r is dipped in water. It holds the water upto a depth of h then the value of r is

$r = \frac{2 T}{hdg}$

$r = \frac{T}{hdg}$

$r = \frac{Tg}{hd}$

None of these

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Explanation

(a) $\frac{2 T}{r} = hdg \Rightarrow r = \frac{2 T}{hdg}$

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In a capillary tube, water rises by 1.2 mm. The height of water that will rise in another capillary tube having half the radius of the first, is

1.2 mm

2.4 mm

0.6 mm

0.4 mm

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Explanation

(b) $h \propto \frac{1}{r} ∴ r_{1} h_{1} = r_{2} h_{2} \Rightarrow h_{2} = \frac{r_{1} h_{1}}{r_{2}} = 2.4 mm$

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If capillary experiment is performed in vacuum, then for a liquid there capillary rise

It will rise

Will remain same

It will fall

Rise to the top

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Explanation

(b)

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If liquid level falls in a capillary then radius of capillary will

Increase

Decrease

Unchanged

None of these

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Explanation

(a) $h \propto \frac{1}{r} ∴ rh = constant$

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Water rises to a height h in a capillary at the surface of earth. On the surface of the moon the height of water column in the same capillary will be

$\frac{1}{6} h$

Zero

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Explanation

(a)

$h = \frac{2 Tcosθ}{rdg} ∴ h \propto \frac{1}{g} As g_{m} = \frac{g_{e}}{6} ∴ h_{m} = 6 h_{e}$

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