Antiseptic chloroxylenol is
Alcohol, phenol & ether MCQs for NEET — Chemistry Questions with Answers
Practice free Alcohol, phenol & ether (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Which of the following industry produces the waste of phenolic compounds and suspended solids ?
Which of the following component causes water pollution ?
The major cause of air pollution in big cities is ...
Choose the proper option for given statement on the basis of physical properties Statement : (i) Alkyl isocyanides have bad odours while alkyl cyanides have pleasant odours. Statement : (ii) Alkyl cynanides are poisonous compounds. Statement : (iii) The boiling points of alkyl cyanides are lower than their isomeric alkyl-isocynides. Statement : (iv) Acetonitrile is soluble in water but methylcarbylamine is not.
Inter molecular hydrogen bonding is strongest in
Intermolecular hydrogen bonding is strongest in methanol compared to methylamine, phenol, and methanal. This is because methanol (CH3OH) has a hydroxyl group (-OH) which can form strong hydrogen bonds with other methanol molecules. The oxygen atom in the hydroxyl group is highly electronegative and can attract hydrogen atoms from neighboring molecules, forming strong hydrogen bonds.
Among the following dissociation constant is highest for
$ CH_3 NH_3 ^+ Cl ^ -$ being asalt, undergoes almostcomplete dissociation, therefore, it has ahigh dissociation constant.
Numbers of isomeric alcohols of molecular formula $C_5H_{12}O $ are
For the molecular formula $C_5H_{12}O$, there are 8 possible isomeric alcohols. These include different structural isomers with variations in the position of the hydroxyl group ($-OH$) and branching of the carbon chain. The isomers can be primary, secondary, or tertiary alcohols, each with a unique structure. Therefore, the correct answer is 8.
Which of the following will produce only one product on reduction with $LiAlH_4$ ?
$CH_3 CH_2 CH_2OH $ Can be converted to $CH_3 CH_2 CH_2COOH$ by the following sequence of steps:
The conversion of $CH_3CH_2CH_2OH$ (1-propanol) to $CH_3CH_2CH_2COOH$ (butanoic acid) involves the following steps: first, reaction with $PBr_3$ to replace the hydroxyl group with a bromine atom to form $CH_3CH_2CH_2Br$ (1-bromopropane). Next, this compound reacts with $KCN$ to form $CH_3CH_2CH_2CN$ (butyronitrile). Finally, hydrolysis of the nitrile with $H_3O^+$ yields the carboxylic acid $CH_3CH_2CH_2COOH$.
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