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Alcohol, phenol & ether MCQs for NEET — Chemistry Questions with Answers

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Which physical state of water is more compressable applying pressure at constant temperature ?

A. Ice B. water C. Vapour D. Plasma

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The number of moles of KMnO4 that will be required to react with 2 mole of ferrous oxalate is

6 by 5

2 by 5

4 by 5

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What is meant by Bose Einstein condensate ?

A. It is the specific state of matter B. Showing relation $ E = MC^2$ for the matter C. It is an electronic device developed by Bose and Einstein D. It is an energy of radiation

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The critical temperature of water is higher than that of O₂ because H₂O molecule has:

fewer electrons than oxygen

two covalent bonds

V-shape

dipole moment

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Explanation

(d) Dipole-dipole attraction give rise to more tendency for aggregation.

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Benzene is oxidized by H₂O₂ in presence of FeSO₄ to:

phenol

cyclohexane

benzaldehyde

benzoic acid

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Density of water is maximum at:

0 $°$ C

100 $°$ C

4 $°$ C

0 K

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Explanation

(c)

The maximum density of water occurs at 4 °C because, at this temperature two opposing effects are in balance. Explanation: In ice, the water molecules are in a crystal lattice that has a lot of empty space. When the ice melts to liquid water, the structure collapses and the density of the liquid increases.

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$H_{2} O$ has higher boiling point than $H_{2} S$ because.

$H_{2} O$ is a smaller molecule and hence more closely packed

The bond angle in $H_{2} O$ is more than in $H_{2} S$ and hence the former molecules are more tightly packed

Of intermolecular hydrogen bonding in liquid $H_{2} O$

The latent heat of vaporisation is higher for $H_{2} O$ than for $H_{2} S$

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Explanation

(C). The b.p of $H_{2} O$ is higher than that of $H_{2} S$ because of intermolecular hydrogen bonding in

liquid $H_{2} O$ .

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The maximum possible number of hydrogen bonds a water molecule can form is –

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Explanation

(B). Water molecules can form two hydrogen bonds through its two hydrogen atoms and another

two with two lone pairs of electrons on the O atom.

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In which of the following reactions is $H_{2} O_{2}$ acting as an acid.

$2 {KMnO}_{4} + 3 H_{2} {SO}_{4} + 5 H_{2} O_{2} \to K_{2} {SO}_{4} + {MnO}_{4} + 2 {MnSO}_{4} + 8 H_{2} O + 5 O_{2}$

$2 K_{3} Fe {(CN)}_{6} + 2 KOH + H_{2} O_{2} \to 2 K_{4} Fe {(CN)}_{6} + 2 H_{2} O + O_{2}$

$O_{3} + H_{2} O_{2} \to H_{2} O + 2 O_{2}$

$Ba {(OH)}_{2} + H_{2} O_{2} \to {BaO}_{2} + H_{2} O_{2}$

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Explanation

(D). $Ba {(OH)}_{2} + H_{2} O_{2} \to {BaO}_{2} + 2 H_{2} O$ is similar to acid base (neutralisation reaction). Aqueous

solution of $H_{2} O_{2}$ is weakly acidic.

$H_{2} O_{2} + H_{2} O \to H_{3} O^{+} + {HO}_{2}^{-}$

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A substance gives off $O_{2}$ when heated, turns an acid solution of $KI$ violet, and reduces acidified ${KMnO}_{4}$ . The substance is –

${SO}_{3}$

${KNO}_{3}$

$H_{2} O_{2}$

All of these

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Explanation

(C). These are the properties of $H_{2} O_{2}$ .

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