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Aldehyde ketones & carboxylic Acid MCQs for NEET — Chemistry Questions with Answers

Practice free Aldehyde ketones & carboxylic Acid (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

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Vanillin, used as a flavouring agent is:

an aliphatic alcohol

an aromatic aldehyde

a hydrocarbon

a carbohydrate

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Explanation

(b) Due to bitter almond smell. It is ${CH}_{3} O (OH) C_{6} H_{3} CHO .$

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Acetophenone on oxidation by perbenzoic acid gives phenyl acetate. The reaction is named as:

Baeyer-Villiger oxidation

Perkin's reaction

Claisen condensation

Reformatsky reaction

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Explanation

(a) The name of reaction is Baeyer-Villiger oxidation.

$C_{6} H_{5} {COCH}_{3} \to_{acid}^{Perbenzoic} C_{6} H_{5} {COOCH}_{3}$

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In Etard's reaction, toluene is oxidised to benzaldehyde using:

H₂O₂

Cl₂

chromium trioxide or CrO₂Cl₂

KMnO₄

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Explanation

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m-chlorobenzaldehyde on reaction with conc. KOH at room temperature gives:

potassium m-chlorobenzoate and m-hydroxybenzaldehyde

m-hydroxybenzaldehyde and m-chlorobenzylalcohol

m-chlorobenzylalcohol and m-hydroxy benzylalcohol

potassium m-chlorobenzoate and m-chlorobenzylalcohol

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Explanation

(d) Cannizzaro's reaction.

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Formylchloride has not been prepared so far. Which can function as formylchloride in formylation ?

HCHO + HCl

HCOOCH₃ + HCl

CO + HCl

HCONH₂ + HCl

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The major product H of the given reaction sequence is:

CH₃-CH₂-CO-CH₃ $\overset{{}_{-}{CN}}{\to}$ G $\to_{Heat}^{95 % H_{2} {SO}_{4}}$ H

${CH}_{3} - CH = \underset{|}{C} - COOH {CH}_{3}$

${CH}_{3} - CH = \underset{|}{C} - CN {CH}_{3}$

$OH {CH}_{3} - CH - C_{|}^{|} - COOH {CH}_{3}$

${CH}_{3} - CH = \underset{|}{C} - CO - {NH}_{2} {CH}_{3}$

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Acetic acid is obtained when:

glycerol is heated with sulphuric acid

methyl alcohol is oxidized with potassium permanganate

acetaldehyde is oxidized with potassium dichromate and sulphuric acid

calcium acetate is distilled in presence of calcium formate

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Explanation

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Main product of the reaction,

CH₃CONH₂+HNO₂ $\to$ ... is:

CH₃COOH

CH₃CH₂NH₂

CH₃NH₂

CH₃COONH₄

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Explanation

(a) CH₃CONH₂ $\overset{{HNO}_{2}}{\to}$ CH₃COOH+H₂O+N₂; the function of HNO₂ is to convert $—$ NH₂gp. to $—$ OH gp.

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The $-$ COOH group in a carboxylic acid can be replaced by 'H' by heating the acid with:

Zn with HCl

H₂in presence of nickel

sodalime

bromine and concentrated aqueous alkali

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Explanation

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The compound which on reduction with LiAlH₄gives two alcohols:

CH₃COOCH₃

CH₃CO-O-OC₂H₅

CH₃COCH₃

CH₃CHO

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Explanation

(a) CH₃COOCH₃ $\overset{{LiAlH}_{4}}{\to}$ CH₃CH₂OH+CH₃OH

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