Aldehyde ketones & carboxylic Acid MCQs for NEET — Chemistry Questions with Answers

Practice free Aldehyde ketones & carboxylic Acid (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Language English हिंदी
Clear Register free for difficulty & keyword filters

The carbonyl carbon and the three atoms attached to it lie in the same plane. This arrangement is a characteristic of:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The NCERT states, 'Thus, the carbonyl carbon and the three atoms attached to it lie in the same plane and the p-electron cloud is above and below this plane. The bond angles are approximately 120° as expected of a trigonal coplanar structure.'

Which of the following resonance descriptions is implied when explaining the high polarity of the carbonyl group?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The context mentions, 'The high polarity of the carbonyl group is explained on the basis of resonance involving a neutral (A) and a dipolar (B) structures as shown.' The dipolar structure (B) would typically show a positive charge on carbon and a negative charge on the more electronegative oxygen.

What is the common feature of aldehydes, ketones, and carboxylic acids?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The summary explicitly states, 'Aldehydes, ketones and carboxylic acids are some of the important classes of organic compounds containing carbonyl group.'

NEET 2023

Identify product (A) in the following reaction:

COCH₃COCH₃

$$\xrightarrow[\text{conc. HCl}]{\text{Zn-Hg}}\ (A) + 2\,\text{H}_2\text{O}$$

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Clemmensen (Zn-Hg/HCl) reduces C=O of ketones completely to CH₂. Each –COCH₃ becomes –CH₂CH₃ (ethyl).

NEET 2023

Complete the following reaction:

$$\text{Cyclohexanone (A)} \xrightarrow{\text{HCN}} \text{cyanohydrin (B)} \xrightarrow[\Delta]{\text{conc. H}_2\text{SO}_4} \text{[C]}$$

[C] is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Conc. H₂SO₄/Δ hydrolyses the –CN to –COOH and dehydrates the adjacent –OH → α,β-unsaturated acid (cyclohexene-1-carboxylic acid).

NEET 2023

Identify the major product obtained in the following reaction:

COCH₃CHO

$$+\ 2\,[\text{Ag(NH}_3)_2]^+ \xrightarrow{\text{OH}^-,\,\Delta}\ \text{major product}$$

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Tollens selectively oxidises –CHO to –COO⁻ (silver mirror); does not touch ketones.

NEET 2024

Fehling's solution 'A' is

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Fehling A is aqueous CuSO₄; Fehling B is alkaline sodium-potassium tartrate.

NEET 2024

Match List I with List II.

List I (Reactions) List II (Reagents/Condition)
A. Bicyclohexyl → 2 cyclohexanone I. PhCOCl / Anhyd. AlCl₃
B. Benzene → diphenyl ketone II. CrO₃
C. Cyclohexanol → cyclohexanone III. KMnO₄ / KOH, Δ
D. Ar–CH₂CH₃ (with –COOK) → ozonolysis product IV. (i) O₃ (ii) Zn–H₂O

Choose the correct answer from the options given below:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

A-III (KMnO₄/KOH), B-I (Friedel–Crafts acylation), C-II (CrO₃), D-IV (ozonolysis).

NEET 2025

The correct order of decreasing acidity of the following aliphatic acids is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

More alkyl (+I) groups decrease acidity. HCOOH (no alkyl) is strongest; the bulky $(\text{CH}_3)_3\text{CCOOH}$ is weakest.

NEET 2025

The major product of the following reaction is: $\text{C}_6\text{H}_5\text{COCH}_2\text{CH}_2\text{CN} \xrightarrow{\text{(i) CH}_3\text{MgBr (excess)}}\xrightarrow{\text{(ii) H}_3\text{O}^+}$

OC≡N(i) CH₃MgBr (excess) (ii) H₃O⁺
You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Excess CH₃MgBr adds to the ketone (→ tertiary alcohol) and to the nitrile (→ imine, then ketone on hydrolysis). Product: a tertiary alcohol at the original carbonyl and a methyl ketone where the –CN was.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Aldehyde ketones & carboxylic Acid question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.