Aldehyde ketones & carboxylic Acid MCQs for NEET — Chemistry Questions with Answers

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Which compound will form Schiff base with carbonyl compounds?

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Explanation

C||RR=O+NH2-R'C||RR=N-R'

N-alkyl or aryl imine is known as Schiff's base.

Gem di-ether is obtained by:

(i) aldehyde, alcohol, H

(ii) ketone, alcohol, H

(iii) ketone, alcohol, OH

(iv) aldehyde, alcohol, OH

Select the correct answer from the codes given below:

Codes:

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Explanation

Gem diether is acetal or ketal.

Which among the following compounds will give addition reaction with water?

(i) CH3-CH=CH2

(ii) CH3-CCH

(iii) CCl3-CHO

(iv) CH3-CHO

Select the correct answer from the codes given below:

Codes:

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Explanation

Aduct of acetaldehyde is unstable.

In the given reaction,

CH3-CN H2O/(A)H2O/H/(B)

(A) and (B) respectively are:

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Which among the following reagents can be used for the test of carbonyl group in laboratory?

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In the reaction sequence,

C6H5-C-CH3NH2OH/H(A)P2O5[X]                      O

[X] will be:

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Consider the following statements for carbonyl compounds:

(i) They give nucleophilic addition reaction.

(ii) Aldehyde is more reactive than ketone for nucleophilic addition reaction.

(iii) β-hydrogen of carbonyl compound is more acidic than α-hydrogen.

(iv) They give addition reaction followed by elimination reaction with NH2-NH-C6H4-CH3.

Of these statements:

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Explanation

 α-hydrogen is more acidic than β-hydrogen

Consider the following statements for a carbonyl compound:

(i) It gives addition reaction

(ii) It gives condensation reaction

(iii) It gives elimination reaction

(iv) It gives oxidation reaction

Of these statements:

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Explanation

its not an elimination reaction alone, its an addition reaction followed by elimination.

Vapour density of an organic compound is 23.0. It contains 52.17% of carbon and 13% of hydrogen. The compound gives iodoform test. The compound is:

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Explanation

(a) Molar mass of compound  is 46 which is of ethanol. It also gives iodoform test.                               

An organic compound X on treatment with acidified K2Cr2O, gives compound Y which reacts with I2, and NaOH to form CHI3. The compound X can be

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Explanation

 

its 2 degree alcohol, which on oxidation gives ketone, and since product will be propanone , so it will give +ve iodoform reaction.

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