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Amines MCQs for NEET — Chemistry Questions with Answers

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A primary amine heated with CS₂ in presence of excess of HgCl₂ gives isothiocyanate. The reaction is called:

Hofmann's bromamide reaction

Hofmann's mustard oil reaction

Perkin's condensation

Hofmann's elimination

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Explanation

The reaction of a primary amine with carbon disulfide (CSâ‚‚) in the presence of excess mercuric chloride (HgClâ‚‚) to form an isothiocyanate is known as the Hofmann's mustard oil reaction. This reaction is used to synthesize isothiocyanates, which have a characteristic pungent odor.

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Reaction of cyclohexanone with dimethylamine in the presence of catalytic amount of an acid forms a compound if water during the reaction is continuously removed. The compound formed is generally known as:

Schiff's base

an enamine

an imine

an amine

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Biuret test is not given by:

proteins

carbohydrates

polypeptides

urea

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Explanation

The Biuret test is a chemical test used to detect the presence of peptide bonds in proteins and polypeptides. It involves treating the sample with a copper(II) salt solution and observing a violet or pink color change. Carbohydrates do not contain peptide bonds, so they do not give a positive Biuret test.

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An aromatic amine (A) was treated with alcoholic potash and another compound (Y) when a foul smelling gas was formed with formula C₆H₅NC. (Y) was formed by reacting a compound (Z) with Cl₂ in the presence of slaked lime. Compound (Z) is:

$C_{6} H_{5} {NH}_{2}$

${CH}_{3} OH$

${CH}_{3} {COCH}_{3}$

${CHCl}_{3}$

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Explanation

$C_{6} H_{5} {NH}_{2} + KOH (Y) \to C_{6} H_{5} NC;$ (Y) is CHCl₃; (Y) is formed from (Z) + Cl₂ + Ca(OH)₂and thus (Z) is CH₃COCH₃.

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Aniline was acetylated. The product on nitration followed by alkaline hydrolysis gave:

o-nitroacetanilide

o- and p-nitroaniline

m-nitroaniline

acetanilide

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Explanation

Aniline, when acetylated, forms acetanilide. Nitration of acetanilide gives a mixture of o-nitroacetanilide and p-nitroacetanilide. Alkaline hydrolysis of these compounds removes the acetyl group, giving a mixture of o-nitroaniline and p-nitroaniline.

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Pyridine possesses :

aromatic nature

unsaturated aliphatic nature

alicyclic nature

aliphatic nature

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Explanation

Pyridine is an aromatic heterocyclic compound consisting of a six-membered ring with five carbon atoms and one nitrogen atom. The presence of the delocalized Ï€-electron system in the ring gives pyridine its aromatic nature, similar to benzene.

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Ammoniacal solution of Ni(CN)₂ reacts with C₆H₆ to produce a light violet coloured crystaline compound of the formula:

$Ni (CN)_{2} \cdot C_{6} H_{5}$

$C_{6} H_{5} {CH}_{3}$

$Ni (CN)_{2} C_{6} H_{6}$

$Ni (CN)_{2} {NH}_{3 \cdot} C_{6} H_{6}$

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The reaction, $C_{6} H_{5} N_{2} Cl \overset{{Cu}_{2} {Cl}_{2} / HCl}{\to} C_{6} H_{5} Cl + N_{2}$ is called:

Etard's reaction

Sandmeyer's reaction

Wurtz-Fitting reaction

Perkin's reaction

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Explanation

(b) Replacement of N₂Cl by halogen atom of CuX-HX from benzene diazonium chloride is called Sandmeyer's reaction.

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When nitrobenzene is treated with Br₂ in presence of FeBr₃, the major product formed is m-bromonitrobenzene. Statements which are related to obtain the m-isomer are:

the relative electron density on meta carbon is more than that of ortho and para positions

loss of aromaticity when Br⁺ attacks at the ortho and para positions and not at meta position

easier loss of H⁺ to regain aromaticity from the meta positions than from ortho and para positions

none of the above

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Explanation

(a) The presence of m-directing groups in benzene nucleus simply decreases electron density at o- and p-, whereas no change in electron density at m-position is noticed.

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The presence of N $H_{4}^{+}$ radical in solution can be detected by:

Fehling’s solution

Benedict’s solution

Schiff's reagent

Nessler’s reagent

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Explanation

+7KI + K⁺ + 3H₂O.

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