An amine is reacted with benzene sulphonyl chloride then a solid compound is formed which is insoluble in alkali. The amine is:
(b) Secondary amine is reacted with benzene sulphonyl chloride to form solid compound which is insoluble in alkali
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An amine is reacted with benzene sulphonyl chloride then a solid compound is formed which is insoluble in alkali. The amine is:
(b) Secondary amine is reacted with benzene sulphonyl chloride to form solid compound which is insoluble in alkali
Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?
key idea: the reagent which can convert -CONH2 group into -NH2 group is used for this reaction. among the given reagents only NaOH/Br convert -CONH2 group into -NH2 group. Thus, it is used for converting acetamide to methyl amine. This reaction is called Hofmann bromamide reaction.
Which one of the following on reduction with lithium aluminium hydride yields a secondary amine?
The reduction of methylisocyanide (CH3NC) with lithium aluminium hydride (LiAlH4) yields methylamine, which is a secondary amine. Nitroethane and acetamide yield primary amines, while methylcyanide forms a primary amine on reduction with LiAlH4.
Which of the following describes the bonding and geometry around the nitrogen atom in amines?
According to the NCERT text, 'Nitrogen orbitals in amines are therefore, sp3 hybridised and the geometry of amines is pyramidal. Each of the three sp3 hybridised orbitals of nitrogen overlap with orbitals of hydrogen or carbon depending upon the composition of the amines. The fourth orbital of nitrogen in all amines contains an unshared pair of electrons.'
What is the accepted IUPAC name for $C_6H_5NH_2$?
The NCERT text states, 'In common system, it is known as aniline. It is also an accepted IUPAC name. While naming arylamines according to IUPAC system, suffix ‘e’ of arene is replaced by ‘amine’. Thus in IUPAC system, $C_6H_5–NH_2$ is named as benzenamine.' Both Aniline and Benzenamine are accepted IUPAC names. However, Aniline is specifically stated as an accepted IUPAC name and is the more commonly recognized form.
An amine derived from ammonia by replacing one hydrogen atom with an alkyl group (R) is classified as:
The NCERT text states, 'Amines are classified as primary (1o), secondary (2o) and tertiary (3o) depending upon the number of hydrogen atoms replaced by alkyl or aryl groups in ammonia molecule. If one hydrogen atom of ammonia is replaced by R or Ar, we get $RNH_2$ or $ArNH_2$, a primary amine (1o).'
Which of the following is the correct IUPAC name for $CH_3CH_2NHCH_3$?
The NCERT text provides an example: '$CH_3NHCH_2CH_3$ is named as N-methylethanamine'. This directly matches the given structure for the question.
In the IUPAC nomenclature of primary amines, what change is made to the alkane name?
The NCERT text states, 'In IUPAC system, primary amines are named as alkanamines. The name is derived by replacement of ‘e’ of alkane by the word amine. For example, $CH_3NH_2$ is named as methanamine.'
What is the common name for $CH_3–CH_2–CH_2–NH_2$?
Table 9.1 in the NCERT context lists '$CH_3–CH_2–CH_2–NH_2$' with the common name 'n-Propylamine' and IUPAC name 'Propan-1-amine'.
How are substituents on the nitrogen atom in secondary and tertiary amines designated in the IUPAC system?
The NCERT text states, 'To name secondary and tertiary amines, we use locant N to designate substituent attached to a nitrogen atom. For example, $CH_3 NHCH_2CH_3$ is named as N-methylethanamine...'
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