Practice free Amines (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Each question given below contains statement - 1 (Assertion) and Statement - 2 (Reason). Each queastion has 4 choices (1), (2), (3) and (4). out of which only one is correct choose the correct option as under : Statement - 1: Aniline is a weaker base than ammonia. Statement - 2: Aniline is resonance stabilized
Each question given below contains statement - 1 (Assertion) and Statement - 2 (Reason). Each queastion has 4 choices (1), (2), (3) and (4). out of which only one is correct choose the correct option as under : Statement - 1: P - nitro anline is a weaker base than p-toludine Statement - 2: The electron with drawing - $ NO_2 $ group in P-nitroaniline makes it a stronger base.
Statement 1 is true because p-nitroaniline is indeed a weaker base than p-toluidine due to the electron-withdrawing nature of the nitro group. Statement 2 is false because the electron-withdrawing -NO2 group actually makes p-nitroaniline a weaker base, not a stronger base.
Each question given below contains statement - 1 (Assertion) and Statement - 2 (Reason). Each queastion has 4 choices (1), (2), (3) and (4). out of which only one is correct choose the correct option as under : Statement - 1: "Benzonitrile can not be prepared by nucleophilic substitution of benzene". Statement - 2: " Benzonitrile can be easily prepared via diazonium salt".
Statement 1 is true because benzonitrile cannot be prepared by nucleophilic substitution of benzene due to the lack of a good leaving group on benzene. Statement 2 is also true because benzonitrile can be easily prepared via diazonium salt. However, Statement 2 is not a correct explanation for Statement 1, as the preparation method via diazonium salt is a separate fact and does not explain the inability to prepare benzonitrile via nucleophilic substitution of benzene.
Each question given below contains statement - 1 (Assertion) and Statement - 2 (Reason). Each queastion has 4 choices (1), (2), (3) and (4). out of which only one is correct choose the correct option as under : Statement - 1: "Gabriel Synthesis is used in the preparation of primary alifatic amines." Statement - 2: "Primary aromatic amine can be prepared by Gabriel synthesis's method."
Gabriel Synthesis is specifically used for the synthesis of primary aliphatic amines and not for aromatic amines. Therefore, Statement - 1 is True and Statement - 2 is False.
Each question given below contains statement - 1 (Assertion) and Statement - 2 (Reason). Each queastion has 4 choices (1), (2), (3) and (4). out of which only one is correct choose the correct option as under : Statement - 1: " The boiling points of alkylisocyanides are lower than their isomeric alkyl cyanides." Statement - 2: "Isocyanide group is polar, so its boiling points is higher than their isomeric alkyl cyanides."
An organic compound (A) on reduction gives compound (B) on treatment with $CHCl_3$ and alcoholic KOH gives (C) on Catalytic reduction gives N - Methyl aniline. The compound (A) is........
The compound (A) is Nitrobenzene which upon reduction gives Aniline (B). When treated with $CHCl_3$ and alcoholic KOH, it forms Phenyl isocyanide (C). On catalytic reduction, Phenyl isocyanide forms N-Methyl aniline. Hence, the correct answer is Nitrobenzene.
Which is formed when $(CH_3)_4 – N – OH$ is heated ?
$ (CH_3)_4.N. OH \xrightarrow [{}] { { \triangle } } [ (CH_3)_3N ]+ CH_3 OH $
Which of the following reactant produced Benzanilide when it treated with aniline ?
Benzanilide is formed when aniline reacts with benzoyl chloride. The reaction is an example of Schotten-Baumann reaction, where an amine reacts with an acyl chloride to form an amide. The equation for the reaction is:
$$ ext{C}_6 ext{H}_5 ext{NH}_2 + ext{C}_6 ext{H}_5 ext{COCl} ightarrow ext{C}_6 ext{H}_5 ext{NHCOC}_6 ext{H}_5 + ext{HCl} $$
Here, benzoyl chloride (C$_6$H$_5$COCl) is the reactant that produces benzanilide when treated with aniline.
Which of the following is the strongest base in aqueous solution ?
Dimethylamine is the strongest base in aqueous solution among the given options. This is because dimethylamine has two electron-donating methyl groups, which increase the electron density on the nitrogen atom, making it more willing to donate its lone pair of electrons. The order of basicity for amines generally follows:
$$ ext{Dimethylamine} > ext{Methylamine} > ext{Trimethylamine} > ext{Aniline} $$
Hence, dimethylamine (CH$_3$)$_2$NH is the strongest base.
How many primary amines are possibile with the formula of $C_4 H_{11} N $ ?
Four (n - butylamine, isobutylamine, sec-butylamine, ter-butylamine)
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