The radius of second Bohr’s orbit is
Atomic Structure MCQs for NEET — Chemistry Questions with Answers
Practice free Atomic Structure (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
For which of the following sets of quantum -numbers an electron will have the highest energy ?
The uncertainty in the position of an electron $ (mass 9.1 \times 10^{–28} g) $ moving with a velocity of $ 3.0 \times10^4 cms^{–1} $ accurate up to 0.011% will be
The uncertainty in the position of a particle is given by the Heisenberg Uncertainty Principle: Δx * Δp ≥ h/4π, where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is Planck's constant. Using the given values and the relation p = mv, the uncertainty in position is calculated to be 0.175 cm.
The radius of hydrogen atom in the ground state is $ 0·53 A ^ \circ , the radius of 3_Li ^{2+} $ in the similar state is
The radius of a hydrogen-like atom is inversely proportional to the nuclear charge (Z). For the Li2+ ion, Z = 3. Since the radius of the hydrogen atom is given as 0.53 Ã…, the radius of Li2+ in the ground state will be 0.53/3 = 0.17 Ã….
Splitting of spectral lines under the influence of magnetic field is called
The splitting of spectral lines due to the influence of a magnetic field is known as the Zeeman effect. It is caused by the interaction between the magnetic dipole moment of the electron and the applied magnetic field.
The total number of orbitals in a shell with principal quantum number ‘n’ is
Which of the following expressions gives the de-Brogiie relationship ?
The de-Broglie relationship relates the wavelength (λ) of a particle with its momentum (p) as λ = h/p, where h is the Planck's constant. By substituting p = mv, we get λ = h/mv, which is the correct expression relating wavelength, mass, and velocity of a particle.
The uncertainty in the momentum of an electron is $ 1·0 \times 10^{–5} kg ms^{–1}. The uncertainty in its position will be (h = 6·62 \times 10^{–34} kg m^2s^{–1} )$
If the radius of first Bohr orbit be $a_0$ , then the radius of third Bohr orbit would be
Radius of Bohr orbit $ = { n ^ 2 \over Z } \times a_0 $
The first emission line in the atomic spectrum of hydrogen in the Balmer series appears at
$ for Balmer series n_1 = 2 and n_2 = 3 for first line $
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