Practice free Chemical Bonding and Atomic Structure (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
A compound is formed by two elements A and B. The element B forms cubic close packed structure and atoms of A occupy 1/3 of tetrahedral voids. If the formula of the compound is $A_x B_y$, then the value of $x + y$ is:
In ccp, atoms = 4; tetrahedral voids = 8. A fills $8/3$. Ratio A:B $= 8/3 : 4 = 2:3$, so formula $A_2B_3$, $x+y=5$.
Amongst the following, the total number of species NOT having eight electrons around central atom in its outer most shell is: NH₃, AlCl₃, BeCl₂, CCl₄, PCl₅
AlCl₃ (6e), BeCl₂ (4e), PCl₅ (10e) — three species without octet. NH₃ and CCl₄ have 8e.
The number of $\sigma$ bonds, $\pi$ bonds and lone pair of electrons in pyridine, respectively are:
Pyridine (C₅H₅N): 5 C–H σ + 6 ring σ = 11 σ; 3 ring π; 1 lone pair on N.
The correct order of energies of molecular orbitals of N₂ molecule is:
For N₂ (Z $\le$ 7) $s$–$p$ mixing pushes $\sigma 2p_z$ above the degenerate $\pi 2p$ pair.
Intermolecular forces are forces of attraction and repulsion between interacting particles that will include:
A. dipole–dipole forces B. dipole–induced dipole forces C. hydrogen bonding D. covalent bonding E. dispersion forces
Choose the most appropriate answer:
Covalent bonding is intra-molecular, not intermolecular.
Match List-I (Oxoacids of Sulphur) with List-II (Bonds):
| List-I | List-II |
|---|---|
| A. Peroxodisulphuric acid (H₂S₂O₈) | I. 2 S–OH, 4 S=O, 1 S–O–S |
| B. Sulphuric acid (H₂SO₄) | II. 2 S–OH, 1 S=O |
| C. Pyrosulphuric acid (H₂S₂O₇) | III. 2 S–OH, 4 S=O, 1 S–O–O–S |
| D. Sulphurous acid (H₂SO₃) | IV. 2 S–OH, 2 S=O |
Peroxodisulphuric has peroxo (O–O); pyrosulphuric has –O– (no peroxo); sulphuric has 2 S=O; sulphurous has 1 S=O.
What fraction of one edge-centred octahedral void lies in one unit cell of fcc?
An edge is shared by 4 unit cells → each edge-centred void contributes 1/4.
Match List I with List II.
| List I (Compound) | List II (Shape/geometry) |
|---|---|
| A. NH₃ | I. Trigonal Pyramidal |
| B. BrF₅ | II. Square Planar |
| C. XeF₄ | III. Octahedral |
| D. SF₆ | IV. Square Pyramidal |
Choose the correct answer from the options given below:
NH₃ trigonal pyramidal; BrF₅ square pyramidal; XeF₄ square planar; SF₆ octahedral.
Match List I with List II.
| List I (Molecule) | List II (Number and types of bond/s between two carbon atoms) |
|---|---|
| A. ethane | I. one σ-bond and two π-bonds |
| B. ethene | II. two π-bonds |
| C. carbon molecule, C₂ | III. one σ-bond |
| D. ethyne | IV. one σ-bond and one π-bond |
Choose the correct answer from the options given below:
Ethane: single σ; Ethene: σ+π; C₂ in MO theory: two π (bond order 2); Ethyne: σ+2π.
Intramolecular hydrogen bonding is present in
Only in the ortho isomer are –OH and –NO₂ close enough to form an intramolecular H-bond.
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