Practice free Chemical Bonding and Atomic Structure (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Identify the correct answer.
$CO_3^{2-}$ has three equivalent canonical forms (one C=O, two C–O⁻ per form, rotated).
Given below are two statements:
Statement I: A hypothetical diatomic molecule with bond order zero is quite stable.
Statement II: As bond order increases, the bond length increases.
In the light of the above statements, choose the most appropriate answer:
Bond order zero means the molecule does not exist / is unstable (I false). Bond length decreases (not increases) with increasing bond order (II false).
Among the given compounds I–III, the correct order of bond dissociation energy of the C–H bond marked with * is:
C–H bond strength rises with s-character: $sp$ (II, alkyne) > $sp^2$ (I, benzene) > $sp^3$ (III, cyclopropane). Hence II > I > III.
Identify the correct orders against the property mentioned: A. $\text{H}_2\text{O} > \text{NH}_3 > \text{CHCl}_3$ – dipole moment. B. $\text{XeF}_4 > \text{XeO}_3 > \text{XeF}_2$ – number of lone pairs on central atom. C. O–H > C–H > N–O – bond length. D. $\text{N}_2 > \text{O}_2 > \text{H}_2$ – bond enthalpy. Choose the correct answer:
A is correct (1.85 > 1.47 > 1.04 D). D is correct (N₂ 945 > O₂ 498 > H₂ 436 kJ/mol). B is wrong (lone pairs: XeF₂ 3 > XeF₄ 2 > XeO₃ 1). C is wrong (bond length N–O > C–H > O–H).
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