For reaction $ Y_2 + 2Z \rightarrow Product $ , rate controlling step is $ Y + ½ Z \rightarrow Q $ . If the concentration of Z is doubled, the rate of reaction will be
Becomes 1.414 times $ Rate = K [ Y ] [ Z ] ^ { 1 /2 } $ $ \therefore New rate =\sqrt 2 . k[Y] [Z] ^ {1 /2 } =1.414 K [Y] [Z] ^ {1/2 } $