Chemical Kinetics MCQs for NEET — Chemistry Questions with Answers

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In gaseous reactions important for the understanding of the upper atmosphere H2O and O react bimolecularly to form two OH radicals. H for this reaction is 72kJ at 500 K and Ea is 77 kJ mol-1, then Ea for the bimolecular recombination of two OH radicals to form H2O and O is:

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Explanation

(c) H2O + O 2OH; H = 72KJ at 500K;

Given Ea = 77KJmol-1

2OH H2O + O ; Ea.B.R 

77=72+Ea.B.R 

Ea.B.R = 5 KJmol-1

 

For a reaction A           Product, rate law is -d[A]dt=K[A]0. The concentration of A left after time t when t=1K is:

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Explanation

(a) For I order reaction:   [A]t=[A]0×e-Kt=[A]0e-K×1K=[A]0e

For the reaction N2 + 3H2  2NH3, the rate d[NH3]/dt = 2x10-4 Ms-1 .Therefore, the rate -d[N2]/dt is given as:

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Explanation

(a) -d[N2]/dt = 1/2d[NH3]/dt

If 'I' is the intensity of absorbed light and 'c' is the concentration of AB for the photochemical process AB + hv→  AB *, the rate of formation of AB * is directly proportional to:

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Explanation

(b) In photo initiated primary process rate of reaction is directly proportional to intensity of light used.

 

In a reaction, the rate expression is, rate = K[A][B]2/3[C]0 , the order of reaction is:

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Explanation

(c) Order of reaction is sum of powers raised on concentration terms in order to write rate expression.

The rate of a reaction get doubles when the temperature changes from 7°C to 17°C. By what factor will it change for the temperature change from 17°C to 27°C?

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Explanation

logk2k1=E02.303R1T1-1T2log2=E02.303RT2-T1T1T20.3=E02.303R×10280×290Ea=0.3×2.303×280×29×R...(1)Now againlogk2k1=E02.303RT2-T1T1T2logk2k1=0.3×2.303×280×29R2.303R10290×300=1.905

For the elementary step,

(CH3)3.CBr(aq) → (CH3)3C+ (aq) + Br- (aq) the molecularity is:

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Explanation

(b) Molecularity represents the number of molecules of reactants taking part in an elementary step of reaction.

The rate of disappearance of SO2 in the reaction; 2S02 +02 → 2S03 is 1.28 x10-3g/sec. Then the rate of formation of SO3 is:

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Explanation

(d) Rate of formation of SO3 = rate of disappearence of SO2

           = 1.28x10-3 g/sec = 1.28x10-3/64 M/sec (64 is the molecular weight of SO2)

           = (1.28x10-3/64)x80 g/sec = 1.60x10-3  g/sec

When ethyl acetate was hydrolysed in pressure of 0.1 N HCl, the rate constant was found to be 5.40 x 10-5 sec-1 . But when 0.1 N H2SO4 was used for hydrolysis, the rate constant was found to be 6.25 X10-5sec-1. Thus, it may be concluded that:

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Explanation

(a) Relative strength in favour of H2SO= rate constant of reaction catalysed by H2SO/ rate constant of reaction catalysed by HCl

The half time of a second order reaction is:

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Explanation

(b) For II order reaction, t1/2 = 1/Ka

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