Chemical Thermodynamics MCQs for NEET — Chemistry Questions with Answers

Practice free Chemical Thermodynamics (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Language English हिंदी
Clear Register free for difficulty & keyword filters

An isolated system-

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(D) An isolated system is one which is separated so that the mass and energy of the system cannot be transferred to or from the surroundings.

The correct calculate value for H for

M(s) M2+(ag)

From following arbitrary value

M(s) M(g) ;H = 1000KJ mol-1M(g) M+(g) ; H = 750KJ mol-1M+(g)M2+(g);H = 1200KJ mol-1M2+(g)+aq M2+(aq.); H = -1800KJ mol-1

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

H =Hsub+IE1+IE2+Hhydration=1000+750+12000+(-1800)H=1150 KJ mol-1

Internal energy and pressure of a gas per unit volume are related as                       

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) The average translational kinetic energy of a gas molecule is 12mu2 at a temperature T. The total energy of the whole of the gas containing N molecules is

                                 Ek12mNu2                      ....(i)

The kinetic gas equation is

                                    pV = 13mNu2                 .... (ii)

                                    pV = 2/3 x 1/2 mNu2  

                                    pV =  23Ek

                                    p = 23Ek per unit volume

Work done in reversible adiabatic process is given by:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(b) This is the derived formula for Wrev in adiabatic process.

Change in enthalpy for reaction,

2H2O2(l) 2H2O(l) + O2(g)

if the heat of formation of H2O2(l) and H2O(l) are -188 and -286 kJ/mol respectively is           

You've reached today's free limit of 20 questions. Log in to keep practising for free.

One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K)(4.0 atm, 5.0 L, 245 K) with a change in internal energy, U = 30.0 L atm. The change in enthalpy (H) of the process in L atm is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(c) H=U + PV

      ... H2-H1 = U2-U1+(P2V2 - P1V1)

      ...     H = 30 + (4x5 - 2x3) = 44 L atm

At absolute zero, the entropy of a perfect crystal is zero. This is........... of thermodynamics.

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(c) This is definition of third law of thermodynamics.

At constant pressure and temperature, the direction of any chemical reaction is one where, the...... decrease.

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(c) Spontaneous process shows a decrease in G

The work done by a mass less piston in causing an expansion V (at constant temperature), when the opposing pressure, P is variable, is given by:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) Wrev-PdV or -PV; note that opposing pressure is not constant throughout.

Entropy decreases during:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) During solidification disorder decreases.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Chemical Thermodynamics question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.