At constant T and P, which one of the following statements is correct for the reaction, $ CO_{(g)} + { 1 \over 2 } O_{2(g) } \rightarrow CO_{2(g) } $
For the reaction $CO_{(g)} + {1 ackslash 2} O_{2(g)} ightarrow CO_{2(g)}$, the enthalpy change (ΔH) is greater than the change in internal energy (ΔE) because the reaction involves a change in the number of moles of gas. At constant temperature and pressure, the enthalpy change includes the pressure-volume work done by the system, making ΔH larger than ΔE.