The gas absorbs 100 J heat and is simultaneously compressed by a constant external pressure of 1.50 atm from 8 lit. to 2 lit. in volume. Hence will be-
Chemical Thermodynamics MCQs for NEET — Chemistry Questions with Answers
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If and then variation of EMF of a cell E, with temperature T, is given by
On comparison :
The standard heat of combustion of Al is -837.8 kJ mol-1 at which of the following releases 250 kcal of heat ?
Thus, the liberation of 250 kcal energy indicating the formation of 0.624 moles of Al2O3
. This R is :
PV=RT at temp T for one mol
at temp. (T+1) for one mol
Heat of neutralisation of oxalic acid is -25.4 K cal mol-1 using strong base, NaOH. Hence enthalpy change of the process is is-
The heat of neutralisation of strong acid and strong base = -13.7 kcal/equiv.
During the isothermal mixing of ideal gases at pressure, p, the entropy change per mole for the mixing process is-R where x1, x2,....,xi are the mole fractions of the components, 1, 2,....,i of the mixture. Assuming ideal gas behavior, calculate for the mixing of 0.8 mole of N2 and 0.2 mole of O2.(at and 0.9 atm) [1 eu = cal/deg]
Mole fractions are 0.8 and 0.2
entropy of mixing per mole
For the reaction :
Heat of hydrogenation of ethene is x1 and that of benzene is x2. Hence resonance energy is-
Resonance energy of benzene (contains three double bond) = 3x1-x2
The bond energies of, C-H, H-H and C=C are 198, 98, 103 and145 kcal respectively. The enthalpy change of the reaction is
The enthalpy change for the given reaction is calculated by considering the number of the various bonds broken in the reactants and the number of new bonds formed in the products.
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