Chemical Thermodynamics MCQs for NEET — Chemistry Questions with Answers

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The gas absorbs 100 J heat and is simultaneously compressed by a constant external pressure of 1.50 atm from 8 lit. to 2 lit. in volume. Hence E will be-

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Explanation

H=E+PV100=E+1.52-8×8.3140.0821E=1011.4 J

If G=H-TS and G=H+TdGdTP then variation of EMF of a cell E, with temperature T, is given by

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Explanation

On comparison : S=dGdTS=d-nFEdT=nFdEdT     dEdT=SnF

The standard heat of combustion of Al is -837.8 kJ mol-1 at 25C which of the following releases 250 kcal of heat ?

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Explanation

Al+34O2=12Al2O3       ;        H=-837.8 kJ250 kcal = 250×4.2 kJ = 1050 kJ1050 kJ heat indicated the formation of12×1050837.8=0.624 moles of Al2O3.

Thus, the liberation of 250 kcal energy indicating the formation of 0.624 moles of Al2O3

CP-CV=R. This R is :

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Explanation

PV=RT at temp T for one mol

PV+V=RT+1 at temp. (T+1) for one mol

 PV=R

Heat of neutralisation of oxalic acid is -25.4 K cal mol-1 using strong base, NaOH. Hence enthalpy change of the process is H2C2O42H++C2H42- is-

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Explanation

The heat of neutralisation of strong acid and strong base = -13.7 kcal/equiv.

 -25.4=-2×13.7×Hdissoor Hdisso=2×13.7-25.4=2 kcal

During the isothermal mixing of ideal gases at pressure, p, the entropy change per mole for the mixing process is-R xi ln xi where x1, x2,....,xi are the mole fractions of the components, 1, 2,....,i of the mixture. Assuming ideal gas behavior, calculate S for the mixing of 0.8 mole of N2 and 0.2 mole of O2.(at 25C and 0.9 atm) [1 eu = cal/deg]

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Explanation

Mole fractions are 0.8 and 0.2

 entropy of mixing per mole

=-1.9870.8 ln0.8+0.2 ln0.2=-1.987-0.1785-0.3219=0.9943 eu

 

For the reaction : X2O4l2XO2gE=2.1 kcal. S=20 cal/K at 300 K. Hence G is :

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Explanation

H=E+ngRT=2.1+2×0.002×300=3.03 kcalG=H-TS=3.3-300×0.02=-2.7 kcal

Heat of hydrogenation of ethene is x1 and that of benzene is x2. Hence resonance energy is-

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Explanation

C6H6+3H2=C6H12                           H=x23C2H4+3H2=3C2H6                     H=x1

 Resonance energy of benzene (contains three double bond) = 3x1-x2

C2H6g+3.5O2g2CO2g+3H2OgSvapH2O, l=x1 cal K-1b.p. +T1HfH2O, l=x2; HfCO2=x3, HfC2H6=x4Hence H for the reaction is-

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Explanation

H=3×HfH2O, g+2HfCO2, g-HfC2H6, gH2OlH2Og HfHf=HfH2O, g-HfH2O, lHf=H2O, g=T1x1+HfH2O, l=T1x1+x2 H=3T1x1+3x2+2x3-x4

The bond energies ofCC, C-H, H-H and C=C are 198, 98, 103 and145 kcal respectively. The enthalpy change of the reaction HCCH+H2C2H4 is

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Explanation

The enthalpy change for the given reaction is calculated by considering the number of the various bonds broken in the reactants and the number of new bonds formed in the products.

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