Classification of elements and Periodicity in properties MCQs for NEET — Chemistry Questions with Answers

Practice free Classification of elements and Periodicity in properties (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

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If a certain element has an atomic number 19, the element is:

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Explanation

(b) It has 1s2, 2s2 2p2, 3s2 3p6, 4s1 electron configuration. It has one electron in their outermost shell, hence, have the tendency to lose it. 

 

Which of the following has the least density?

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Explanation

Li has minimum density.

density increases down the grp,exception is Na ,which is having higher density than K.

Eka aluminium and eka silicon are now known as:

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Explanation

(a) 

eka was used to indicate element place below in the group. so element below aluminium or element below silicon

An element having the electronic configuration of its atom ns2 np2 should have similar properties to those of:

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Explanation

(b) 6C has electronic configuration 1s2 , 2s2 2p2

The order of basic character of given oxides is:

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Explanation

(a) According to their metallic character which decreases from Na to Cu.

 

higher  the metallic character, higher the basic nature of their oxide.

the lightest metal in the periodic table is:

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Explanation

Mass no. of metal increases along the period and down the group also.

Which electronic configurations represent to a transition element?

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Explanation

The differentiating electron enters in d-sub-shell.

 

Low melting point of manganese in the 1st transition series is due to:

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Explanation

(b) Due to d5 configuration, metallic bonds are weak. d5  orbital is half filled as a result of that 3d electrons are more tightly held by the nucleus and this reduces the de-localization of electrons resulting in weaker metallic bonding.

 

Most common oxidation state of cerium (Ce) is :

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Explanation

 E.C of  Ce is [Xe]4f15d16s2,

The common stable oxidation state of all the lanthanides is +3. The oxidation states of +2 and +4 are also exhibited and these oxidation states are only stable in those cases where stable 4f0, 4f7 or 4f14 configurations are achieved. Ce4+ is stable due to 4f0 configuration.

Which of the electronic configuration of an atom has the lowest ionization enthalpy? 

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Explanation

I.E is inversly proportional to size ..

and valance electron should be lesser.

 

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