D & F Block Elements MCQs for NEET — Chemistry Questions with Answers

Practice free D & F Block Elements (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

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Which of the following is true for the species 3d4 configuration ?

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Explanation

(C)

    Cr2+ is reducing as its configuration changes from d4 and d3, the latter having a half-filled t2g level.

    On the other hand, the change from Mn3+ to Mn2+ results in the half-filled d5 configuration which

    has extra stability.

In which compound does vanadium have an oxidation number of +4?

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Explanation

(D)  VOSO4=VO2++SO42-;  x+-2=+2=+4.

Among the following, the species that is both paramagnetic and coloured is :

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Explanation

(A)

     MnO42-; Mn is in +6 oxidation state. Electronic configuration is Ar183d14s0. As it contains

      one unpaired electron it is paramagnetic and green coloured because of d-d transition in visible

      region. TiCl62-, VO43- and CrO2Cl2 are diamagnetic as all electrons are paired.

Arrange the following species in the increasing order of their magnetic properties.

VCl3    VOSO4    Na3VO4       VH2O6SO4.H2O

  I              II                  III                      IV

 

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Explanation

(A)

    (I) VCl3; V3+23; Ar183d2=2 unpaired electrons.

    (II) VO2+; V4+; Ar183d2=1 unpaired electrons.

   (III) VO43-; V5+; Ar183d0= no unpaired electrons.

    (IV) VH2O62+; V2+; Ar183d3=3 unpaired electrons.

Which of the following increasing order of oxidising power is correct for the following species?

           VO2+, MnO4-, Cr2O72-

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Explanation

(A)  This is due to the increasing stability of the lower species to which they are reduced.

In which of the following oxoanions the oxidation state of the central atom is not the same as that of its group number in the periodic table?

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Explanation

(D)

     (A) MnO4-=+7; Ar18 3d5 4s2=7.                             (B) Cr2O72-=+6; Ar18 3d5 4s1=6.

     (C) VO43-=+5; Ar18 3d3 4s2=5.                               (D) FeO42-=+6; Ar18 3d6 4s2=8.

At 300°C, FeCl3 :

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Explanation

  True statement, 2FeCl3   300°C   FeCl32g

Anhydrous ferric chloride is prepared by

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Explanation

(B)

    (B) 2Fe+3Cl2                 2FeCl3anhydrous; A, C, D do not give anhydrous FeCl3 but 

    hydrated FeCl3.

Anhydrous ferrous sulphate on heating gives :

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FeCl3.6H2O+C CH32CH3O2Products

Reaction products are :

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Explanation

(A)   FeCl3.6H2O+CH-C||OCH3OCH3-CH3FeCl3+12CH3OH+6CH3COOH3

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