If concentration of the $ Cu ^{2+} _{(aq)} is made double then what change is observed in the E ^ 0 _cell Cu_{(s)} + 2Ag^{2+}_{(äq)} \rightleftharpoons Cu^{2+}_{(aq)}+ 2Ag_{(s)} E ^\circ = 0.48 Volt $ for the reaction
The Nernst equation for the given cell is: E_cell = E^0_cell - (RT/nF) ln(Q), where Q is the reaction quotient. Doubling the concentration of Cu^{2+}_{(aq)} does not affect the standard cell potential (E^0_cell), as it depends only on the standard reduction potentials of the half-reactions involved. Therefore, the cell potential (E_cell) remains unchanged.