Blog Log in Get Started Free

Equilibrium MCQs for NEET — Chemistry Questions with Answers

Practice free Equilibrium (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology

Language English हिंदी

Chapter Difficulty Show only questions I answered incorrectly Clear Register free for difficulty & keyword filters

● ● ● ● ●

N₂O₄ dissociates as $N_{2} O_{4} (g) ⇌ 2 {NO}_{2} (g)$ at 273 K and 2 atm pressure. The equilibrium mixture has a vapour density of 41. What will be the percentage degree of dissociation ?

14.2%

16.2%

12.2%

87.8%

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Use,

$α = \frac{D - d}{(n - 1) d}$

D=Theorotical vapour dessity

d= Observed apour density

n= No. of moles obtained after dissociation after one mole

$α = \frac{46 - 41}{(2 - 1) 41} = 0.122$

% dissociation = 12.2%

● ● ● ● ●

On the adding inert gas to the equilibrium ${PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g)$ at constant pressure. The degree of dissociation will :

Unchanged

Decreased

Increased

May be decrease or increase

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

On adding inert gas at constant pressure, equilibrium shifts in tht direction where the number of moles are more.

● ● ● ● ●

The stability product constant K_spof Mg(OH)₂ is 9.0 X 10^-12. If a solution is 0.010 M with respect to Mg²⁺ ion, waht is the maximum hydroxide ion concentration which could be present without causing the precipitation of Mg(OH)₂

1.5 X 10^-7 M

3.0 X 10^-7 M

1.5 X 10^-5 M

3.0 X 10^-5 M

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$Mg (OH)_{2} ⇌ {Mg}^{2 +} + 2 {OH}^{-} K_{sp} = [{Mg}^{2 +}] [{OH}^{-}]^{2} 9 \times 10^{- 12} = 0.01 \times [{OH}^{-}]^{2} [{OH}^{-}] = 3 \times 10^{- 5} M$

● ● ● ● ●

Which may be added to one litre of water to act as a buffer

One mole of HC₂H₃O₂ and 0.5 mole of NaOH

One mole of NH₄Cl and one mole of HCl

One mole of NH₄OH and one mole of NaOH

One mole of HC₂HO and one mole of HCl

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

${CH}_{3} COOH + NaOH \to {CH}_{3} COONa + H_{2} O$

At t=0 1 0.5 0 0

Att t='t' 0.5 0 0.5 0.5

Now it is the acidic buffer solution.

● ● ● ● ●

Acoording to Bronsted-Lowry concept, the correct order of relative strength of bases follows the order

CH₃COO^- > Cl^- > OH^-

CH₃COO^- > OH^- > Cl^-

OH^-> CH₃COO^- > Cl^-

OH^- > Cl^-> CH₃COO^-

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

All weak acid has strong conjugate base and strong acid has weak conjugate base.

● ● ● ● ●

pOH of H₂O is 7.0 at 298K. If water is heated at 350K, which of the following statement should be true ?

pOH will decrease

pOH will increase

pOH will remain 7.0

Concentration of H⁺ ions will increase but that of OH^- will decrease.

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

On heating dissociationof H₂O increases. SO, [H⁺] as well s [OH^-] increases and pH as well as pOH decreases.

● ● ● ● ●

In which case following equilibrium can't be established:

CaCO₃(s) $⇌$ CaO(s) + CO₂(g)

Some CaO & pressure of CO₂ was greater than Kp

Pure CaCO₃

Some CaCO₃ & pressure of CO₂ gas greater than K_p

Some CaCO₃ & pressure of CO₂ gas less than K_p.

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

When pressure of CO₂ gas greater than K_p then it can't shift in backward direction without CaO.

● ● ● ● ●

Solubility product constant (K_sp) of salts of types MX,MX₂ and M₃X at temperature T are 4.0 X 10^-8, 3.2 X 10^-14 and 2.7 X 10^-15 respectively. Solublities(mol dm^-3) of the salts at temperature T are the order:

MX > MX₂> M₃X

M₃X > MX₂ > MX

MX₂> M₃X > MX

MX > M₃X > MX₂

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

For Mx, K_sp=S²

For MX_2,K_sp=4S³

For M₃X, K_sp =27S⁴

Use the above formula and calculate the solubilities.

● ● ● ● ●

At 25 $°$ C the specific conductance of sturated solution of AgCl is 2.3 X 10-6 ohm^-1cm^-1. What will be the solubility of AgCl at 25 $°$ C if iconic conductances of ${Ag}^{\oplus}$ and ${Cl}^{⊝}$ at infinite dilution are 61.9 and 76.3 ohm^-1cm²mol^-1 respectively.

1.66 X 10^-11M

3.18 X 10^-6M

6.01 X 10^-5M

1.66 X 10^-5M

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$Solubility (S) = \frac{K \times 1000}{Λ_{m}^{\infty}} = \frac{2.3 \times 10^{- 6} \times 1000}{61.9 + 76.3} = \frac{2.3 \times 10^{- 3}}{138.2} = 1.66 \times 10^{- 5} mol / L$

● ● ● ● ●

In the reaction, N₂O₄ $⇌$ 2NO₂, $α$ is that part of N₂O₄ which dissociates, then the number of moles at equilibrium will be:

${(1 - α)}^{2}$

$3 α$

$α$

$1 + α$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

4. N₂O₄ $⇌$ 2NO₂

1 0 ---- at zero times

1- $α$ 2 $α$ ---- at equilibrium

No. of moles at equilibrium = 1- $α$ +2 $α$ = 1+ $α$

Ready to ace NEET?

Free access · No credit card required

Browse All Questions Create Free Account

Frequently Asked Questions

Yes. You can attempt every Equilibrium question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.