Hydrocarbons MCQs for NEET — Chemistry Questions with Answers

Practice free Hydrocarbons (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Language English हिंदी
Clear Register free for difficulty & keyword filters

In Friedel-Craft's synthesis of toluene, the reactants in addition to anhydrous AlCl3 are

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

In the Friedel-Crafts alkylation of benzene to produce toluene, the reactants are benzene (C6H6) and methyl chloride (CH3Cl) in the presence of anhydrous aluminum chloride (AlCl3) as a Lewis acid catalyst. The methyl group from methyl chloride gets attached to the benzene ring, forming toluene.

The reaction of toluene with Cl2 in the presence of FeCl3 gives 'X' and reaction in presence of light gives 'Y'. Thus, 'X' and  'Y' are

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Acetylenic hydrogens are acidic because

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Acidic character of alkynes can be explained on the basis of sp-hybridisation state of the carbon atom in alkynes. We know that an electron in s orbital is more tightly held than in a p orbital because s-electrons are more closer to the nucleus. In sp-hybridisation, s-character is more (50%) as compared to sp2-(33%) orsp3-(25%) hybrid orbitals. Due to very large s-character, the electrons in sp-hybrid orbitals are held tightly by the nucleus and are quite electronegative. Consequently, the electron pair of H-C bond gets displaced more towards the carbon atom and help in the release of H+ ions.

For  example ethyne react with sodium metal and release the H+ ions.

           CHCH + NaHCC-Na+

A compound is treated with NaNH2 to give sodium salt. Identify the compound.

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) Sodamide is strong base, attracts the more acidic hydrogen and gives sodium salt

H-CC-H + NaNH2 H-CC-Na+ + 12H2

                                            Sodium ethynide

Ethylene forms ethylene chlorohydrin by the action of:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Cl2+H2OHOCl+HClhypochlorous AcidCH2=CH2HOClCH2|OH-CH2|Cl Ethylene chlorohydrin

 

 

Ozonolysis of buta-1,3-diene gives:

You've reached today's free limit of 20 questions. Log in to keep practising for free.

The product formed during the reaction,

CHCH + NaOCl 0°C is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) CHCH0°CNaOClCClCCl

2-methylpropene is isomeric with butene-1. They can be distinguished by:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) The ozonolysis of these two produces different products.

Nitration of benzene is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(b) Replacement of H-atom of ring usually takes place following SE reaction mechanism.

Which of the following compounds has the lowest boiling point?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) Boiling points of alkanes increase as the number of carbon atom increase or molecular mass increase. Alkenes have high boiling point, so CH3CH2CH2CH3 has the lowest boiling point.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Hydrocarbons question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.