Hydrocarbons MCQs for NEET — Chemistry Questions with Answers

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Consider the following statements :

a. CH3 group is o, p-directing group due to hyperconjugation.

b. CCl3 is meta directing group due to reverse hyperconjugation.

c.CCl3  group is meta directing group due to mesomeric effect.

d. CHO group is m-directing group 

Of these statements :

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In the given reaction,

C6H5-CC-CH3Na/NH3(l)[X]

[X] will be 

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In which compounds addition reaction will take place according to anti-Markovnikov's rule?

(i) H2C=CH-NO2

(ii) H2C=CH-CHO

(iii) H2C=CH-CN

(iv) CH3-CH=CH2

Select the correct  answer from the codes given below:

Codes:

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Explanation

Alkene having following structure gives anti Markovnikov addition H2C=CH-Z where Z is strong -I group.

Consider the following statements:

(i) Alkene is more reactive than alkyne for electrophilic addition reaction.

(ii) Alkyne gives nucleophilic as well as electrophilic addition reaction.

(iii) Alkyne is more reactive than alkene for nucleophilic addition reaction.

(iv) For electrophilic addition reaction, RI of alkyne is alkyl carbonation.

Of these, correct statements are:

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Explanation

 

R-CCH+HR-C=CH2vinylcarbocation

Which compound is least reactive for nucleophilic addition reaction?

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The reaction, CH2=CHCHOHXgives:

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Explanation

The given reaction is an example of addition of hydrogen halide (HX) to an alkene (ethene). According to Markovnikov's rule, the hydrogen atom gets added to the carbon with fewer hydrogen atoms, and the halide (X) gets added to the carbon with more hydrogen atoms. Hence, the product is CH2=CHCHO.

The reagent used in dehalogenation process is:

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Explanation

Zn dust is used for dehalogenation,

CH2X·CH2Xalc.Zn dustCH2=CH2

Zn-Cu couple used as reducing agent is:

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Explanation

 

Zinc-copper couple, which can be used as a reducing agent, is obtained by coating zinc with copper. Zinc is dipped in a solution of copper salt. It displaces copper and copper gets deposited over the surface of  granulated zinc.

Which reaction sequence would be best to prepare 3-chloro-aniline from benzene?

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Explanation

To prepare 3-chloroaniline from benzene, the best sequence is: nitration (to introduce -NO2 group), chlorination (to introduce -Cl group at 3-position), and finally reduction (to convert -NO2 to -NH2). Nitration is carried out first as the nitro group is a strong deactivating group.

An unknown compound A has a molecular formula C4H6. When A is treated with excess of Br2 a new substance B with formula C4H6Br4 is formed. A forms a white ppt. with ammoniacal silver nitrate solution. A may be:

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Explanation

(a) A white precipitate with am. AgNO3 confirms the presence of terminal alkyne.

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