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Solutions NEET Questions — Free MCQ Practice

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Which of the following is applicable for the solubility of gases in liquid

A. Increases with increase in temperature and pressure. B. decreases with increase in temp and pressure. C. Increases with decrease in temp and increase in pressure. D. Decreases with decrease in temp and increase in pressure.

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Concentration of lead metal in a blood of any person is more than that of 10microgram. $ dm^{-1} $ , than that person is considered as on effect of poision sectrion. Then calculate its concentration in ppb (parts per billion)

A. 1 B. 10 C. 100 D. 1000

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The ratio of $ { RT \over \pi } of 6 \% w/v and 9 \% w/v $ is one for both. what would be the value of atomic weight of A and Brespectively. $ (AB_2 and A_2B are electrolytes) $

A. 60, 90 B. 40, 40 C. 40, 10 D. 10, 40

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Decrease in vapour pressure of an aqueous soln. of an electrolyte is 4% what would be the percentage increase in elevation in Boiling point ? $ (k_b = 0.512 k. kg. mol^{-1}) $

A. 0.55% B. 0.02% C. 5.50% D. 2%

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Boyle's law is applicable in :

A.

isobaric process

B.

isochoric process

C.

isothermal process

D.

adiabatic process

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Explanation

(c) A constant temperature refers for isothermal process.

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The vapour density of undecomposed N₂O₄ is 46. When heated, vapour density decreases to 24.5 due to its dissociation to NO₂. The percent dissociation of N₂O₄ at the final temperature is:

A.

87

B.

60

C.

40

D.

70

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Explanation

(a) normal molar mass/exp. molar mass = 1+ $α$ ; (Molar mass = 2 x VD)

M1 =2*46=92

m2=2*24.5=49

92/49 = 1+ $α$

.^.. $α$ =0.87

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At 298 K, 500cm³ H₂O dissolved 15.30 cm³ CH₄(STP) under a partial pressure of methane of one atm. If Henery's law holds, what pressure is required to cause 0.001 mole methane to dissolve in 300cm³ water ?

A.

0.286 atm

B.

2.486 atm

C.

1.286 atm

D.

3.111 atm

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The molal depression constant for water=1.85 deg/molal and for benzene is 5.12 deg/molal. If the ratio of the latent heats of fusion of benzene to water is 3:8, calculate the freezing point of benzene.

A.

5.75 $° C$

B.

5.12 $° C$

C.

4.97 $° C$

D.

6.1 $° C$

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Which of the following colligative properties is associated with the concentration term 'molarity'?

A.

Lowering of vap.pressure

B.

Osmotic pressure

C.

Depression in freezing point

D.

Elevation in boiling point

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Explanation

(b) p=CRT where c is the molarity of the solution. Hence, osmotic pressure is only associated with the molarity of the solution.

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The K_sp (25 $° C$ ) of sparingly soluble salt XY₂(s) is 3.56X10^-5(mol lit^-1)³ and at 30 $° C$ the vapour pressure of its saturated solution in water is 31.78 mm Hg. Calculate the enthalpy change of the reaction.

${XY}_{2} (s) \overset{}{⇌} X^{2 +} (aq) + 2 Y^{-} (aq)$

Given: Vapour pressure of pure water=31.82 mm Hg

A.

42.5 kJ/mol.

B.

32.1 kJ/mol.

C.

24.5 kJ/mol.

D.

52.5 kJ/mol.

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Explanation

(d) Let the solublity of AB₂(s) at 30 $° C$ be 's' mol Lit^-1

${AB}_{2} (s) \overset{}{⇌} A^{2 +} (aq) + 2 B^{-} (aq)$

s 2s

$\frac{P^{0} - P_{s}}{P_{s}} = \frac{n}{N}; \frac{31.82 - 31.78}{31.78} = \frac{3 s}{55.56}$

s=0.0233 mol/lit

$K_{sp} (at 30 ° C) = (0.0233) (2 \times 0.0233)^{2} = 5.05 \times 10^{- 5} (mol / lit)^{3} K_{sp} (at 25 ° C) = 3.56 \times 10^{- 5} (mol / lit)^{3} Now, \log \frac{K_{sp} (30 ° C)}{K_{sp} (25 ° C)} = \frac{∆ H}{2.303 R} [\frac{T_{2} - T_{2}}{T_{1} T_{2}}] \log (\frac{5.05 \times 10^{- 5}}{3.56 \times 10^{- 5}}) = \frac{∆ H}{2.303 \times 8.314} (\frac{5}{303 \times 298}) ∆ H = 52.5 kJ / mol$

Solutions MCQs for NEET — Chemistry Questions with Answers

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