An aqueous solution of 6.3g oxalic acid dihydrate is made upto 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is
$ Equivalents of H_2C_2O_4 . 2H_2O in 10ml = Equivalents of NaOH $ $ \therefore { 6.3 \times 1, 0000 \over 63 \times 250 \times 0.1 } = V = 40mL $
