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Chemistry NEET Questions — Free MCQ Practice

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Deamination (or) diazotization of n-Bu-NH2 with NaNO₂/HCl gives ......... isomeric butene.

A.

2

B.

3

C.

4

D.

5

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Explanation

Deamination (or diazotization) of n-Bu-NH2 with NaNO2/HCl gives a mixture of three isomeric butenes: 1-butene, cis-2-butene, and trans-2-butene. Therefore, the answer is 3 isomeric butenes.

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Lassaigne's test for the detection of nitrogen will fail in the case of :

A.

NH₂CONH₂

B.

NH₂CONHNH₂.HCl

C.

NH₂NH₂.HCl

D.

C₆H₅NHNH₂.2HCl

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Explanation

(C) NH₂-NH₂(inorganic compound give -ve Lassaigne's test)

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Identify the product (A) in following reaction series,

CH₃CN $\overset{Na / C_{2} H_{5} OH}{\to}$ (X) $\overset{{HNO}_{2}}{\to}$ (Y) $\overset{[O]}{\to}$ (Z) $\overset{Tollens reagent}{\to}$ (A):

A.

CH₃CHO

B.

CH₃CONH₂

C.

CH₃COOH

D.

CH₃-CH₂-NHOH

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Explanation

(c) CH₃CN $\overset{Na / C_{2} H_{5} OH}{\to}$ CH₃CH₂NH₂ $\overset{{HNO}_{2}}{\to}$ CH₃CH₂OH $\overset{[O]}{\to}$ CH₃CHO $\overset{Tollens reagent}{\to}$ CH₃COOH

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The product C of the reaction,

CH₃CN $\overset{H_{2} O}{\to}$ A $\overset{{NH}_{3}}{\to}$ B $\overset{∆}{\to}$ C is:

A.

methyl amine

B.

ammonium acetate

C.

ethyl amine

D.

acetamide

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Explanation

(d) CH₃CN $\overset{H_{2} O}{\to}$ CH₃COOH $\overset{{NH}_{3}}{\to}$ CH₃COONH₄ $\overset{∆}{\to}$ CH₃CONH₂+H₂O

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Gabriels phthalimide reaction is used to prepare:

A.

p-amine

B.

s-amine

C.

t-amine

D.

all of those

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Gas evolved during the reacton of sodium metal on ethyl-amine is:

A.

N₂

B.

C₂H₂

C.

H₂

D.

CO₂

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Explanation

(c) $C_{2} H_{5} {NH}_{2} 1 + Na \overset{}{\to} C_{2} H_{5} NHNa + \frac{1}{2} H_{2}$

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Ethylamine undergoes oxidation in the presence of KMnO₄followed by hydrolysis to form:

A.

an acid

B.

an alcohol

C.

an aldehyde

D.

a N-oxide

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Explanation

$C_{2} H_{5} {NH}_{2} \overset{[O]}{\to} {CH}_{3} CH = NH \overset{KOH}{\to} {CH}_{3} CHO + {NH}_{3}$

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Hinsberg's method to separate amines is based on the use of:

A.

benzene sulphonyl chloride

B.

benzene sulphonic acid

C.

ethyl oxalate

D.

acetyl chloride

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Explanation

(a)

Amines serve as nucleophiles in attacking the sulfonyl chloride electrophile, displacing chloride. The sulfonamides resulting from primary and secondary amines are poorly soluble and precipitate as solids from solution:

PhSO₂Cl + 2 RR'NH → PhSO₂NRR' + [RR'NH₂⁺]Cl⁻

For primary amines (R' = H), the initially formed sulfonamide is deprotonated by base to give water-soluble sulfonamide salt (Na[PhSO₂NR]):

PhSO₂N(H)R + NaOH → Na⁺[PhSO₂NR⁻] + H₂O

Tertiary amines promote hydrolysis of the sulfonyl chloride functional group, which affords water-soluble sulfonate salts.

PhSO₂Cl + R₃N + H₂O → R₃NH⁺[PhSO₃⁻

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An amine reacts with $C_{6} H_{5} {SO}_{2} Cl$ and the product is soluble in alkali, amine is:

A.

$1 °$

B.

$2 °$

C.

$3 °$

D.

all of these

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Explanation

(a) $R {NH}_{2} + C_{6} H_{5} {SO}_{2} Cl \overset{}{\to} C_{6} H_{5} {SO}_{2} NH R$

(Sulphonamide

soluble in alkali)

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When $({NH}_{4})_{2} {SO}_{4} + KCNO are heated, we get :$

A.

nitrogen

B.

carbon dioxide

C.

biuret

D.

amminium carbonate

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Explanation

(c) ${NH}_{4} CNO \overset{∆}{\to} {NH}_{2} {CONH}_{2} \overset{}{\to} {NH}_{2} {CONHCONH}_{2}$

Urea Biuret

Chemistry MCQs for NEET — Practice Questions with Answers

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