Chemistry MCQs for NEET — Practice Questions with Answers

Practice free Chemistry NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Register free to filter questions

Mark the correct statement:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Methylamine (CH3NH2) is a stronger base than ammonia (NH3) due to the electron-donating effect of the methyl group. The methyl group increases the electron density on the nitrogen atom, making it more basic compared to ammonia.

A colourless organic compound gave brisk effervescence with a mixture of NaNO2 and dil.HCl. It could be:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Urea (CO(NH2)2) is the correct answer. When urea is treated with a mixture of sodium nitrite (NaNO2) and dilute hydrochloric acid (HCl), it undergoes a reaction that generates nitrogen gas, causing brisk effervescence.

Aliphatic amines are soluble in water because:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Aliphatic amines are soluble in water because of their ability to form hydrogen bonds with water molecules. The nitrogen atom in amines has a lone pair of electrons, which can form hydrogen bonds with the hydrogen atoms of water molecules.

Which of the following reagents will convert nitromethane into methylamine ?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

 CH3NO2 or Sn/HClZn/HClCH3NH2

Nitrobenze on reduction with Al-Hg and water gives:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) C6H5NO2 Neutral med.Al-Hg/waterC6H5NHOH

                                      Phenylhydroxylamine

The reduction of CH3CN to CH3CH2NH2 is called:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(c) The conversion of -CN to -CH2NH2 by catalytic reduction is called Mendius reaction.

Aniline and ethylamine resembles in:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(c) Both gives alkane (RH) with Grignard reagents RMgX due to the presence of acidic hydrogen (N-H).

Mendius method of preparation of amines consists of: 

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) R-CN ReductionRCH2CH2

The correct order of basicities of the following compounds is:

CH3-C||||NH2NH1,  CH3CH2NH22 , CH32NH3 ,  CH3-C||O-NH24

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

 Negative charge developed on N in the resonance hybride makes it more basic as it loses electron pair readily. Also 2° amine is more basic than 1° amine due to +ve IE of alkyl group. In amide, the lone pair remains less avaible due to delocalisation is resonance.

A primary amine heated with CS2 in presence of excess of HgCl2 gives isothiocyanate. The reaction is called:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The reaction of a primary amine with carbon disulfide (CSâ‚‚) in the presence of excess mercuric chloride (HgClâ‚‚) to form an isothiocyanate is known as the Hofmann's mustard oil reaction. This reaction is used to synthesize isothiocyanates, which have a characteristic pungent odor.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Chemistry question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.