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Chemistry MCQs for NEET — Practice Questions with Answers

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Following is the list of some aromatic compounds. Select the correct sequence of decreasing order of reactivity for electrophilic arpmatic substitution reaction using the answer codes given below:

a. $C_{6} H_{5} - OH$

b. $C_{6} H_{5} - {CH}_{3}$

c. $C_{6} H_{5} - {NO}_{2}$

d. $C_{6} H_{5} - CHO$

Answer codes :

a d b c

c d b a

a b d c

a b c d

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Explanation

Dear OH is more Electronically rich ring as OH is +R group....

Then CH3 group because it Electron donating group by +I effect

Then CHO then NO2 because CHO is less Electron withdrawing group than NO2....

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Consider the following statements :

a. ${CH}_{3}$ group is o, p-directing group due to hyperconjugation.

b. ${CCl}_{3}$ is meta directing group due to reverse hyperconjugation.

c. ${CCl}_{3}$ group is meta directing group due to mesomeric effect.

d. CHO group is m-directing group

Of these statements :

a and b are correct

a and c are correct

a, b and d are correct

c and d are correct

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Which among the following compounds has minimum pH value?

butane

2-butene

1-butyne

2-butyne

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Explanation

Among the given options, 1-butyne has the minimum pH value as the triple bond is more acidic than double and single bonds due to the greater s-character of the sp-hybridized carbon atom, making the hydrogen more acidic.

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In the given reaction,

$C_{6} H_{5} - C \equiv C - {CH}_{3} \overset{Na / {NH}_{3} (l)}{\to} [X]$

[X] will be

1-phenylpropane

1-phenylpropene

trans-1-phenyl propene

cis-1-phenylpropene

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In which compounds addition reaction will take place according to anti-Markovnikov's rule?

(i) $H_{2} C = C H - N O_{2}$

(ii) $H_{2} C = C H - C H O$

(iii) $H_{2} C = C H - C N$

(iv) $C H_{3} - C H = C H_{2}$

Select the correct answer from the codes given below:

Codes:

(i), (ii) and (iii)

(i), (ii) and (iv)

(i) and (ii)

(i) and (iii)

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Explanation

Alkene having following structure gives anti Markovnikov addition $H_{2} C = C H - Z$ where Z is strong -I group.

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Consider the following statements:

(i) Alkene is more reactive than alkyne for electrophilic addition reaction.

(ii) Alkyne gives nucleophilic as well as electrophilic addition reaction.

(iii) Alkyne is more reactive than alkene for nucleophilic addition reaction.

(iv) For electrophilic addition reaction, RI of alkyne is alkyl carbonation.

Of these, correct statements are:

only (i)

(i) and (ii)

(i), (ii) and (iv)

(i), (ii) and (iii)

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Explanation

$R - C \equiv CH + \overset{\oplus}{H} \to \underset{vinylcarbocation}{R - \overset{\oplus}{C} = {CH}_{2}}$

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Which compound is least reactive for nucleophilic addition reaction?

$C_{6} H_{5} CHO$

$C_{6} H_{5} - \overset{O}{\overset{| |}{C}} - {CH}_{3}$

$C_{6} H_{5} - \overset{O}{\overset{| |}{C}} - C_{6} H_{5}$

${CH}_{3} - \overset{O}{\overset{| |}{C}} - {CH}_{3}$

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Arrange the reactivity of given carbonyl compounds in decreasing order for addition reaction:

(i) $C H_{2} B r - C H O$

(ii) $C H_{2} C l - C H O$

(iii) $C H_{2} I - C H O$

(iv) $C H_{3} - C H O$

Select the correct answer from the codes given below:

Codes:

(iv), (iii), (ii), (i)

(ii), (i), (iii), (iv)

(ii), (i), (iv), (iii)

(i), (ii), (iii), (iv)

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Explanation

$R e a c t i v i t y α - I p o w e r o f t h e g r o u p$

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Arrange the reactivity of the given compounds in decreasing order for addition followed by elimination reaction:

(i) p-Cl $- C_{6} H_{4} - C H O$

(ii) p-Br $- C_{6} H_{4} - C H O$

(iii) p-F $- C_{6} H_{4} - C H O$

(iv) p-I $- C_{6} H_{4} - C H O$

Select the correct answer from the codes given below:

Codes:

(i), (iii), (ii), (iv)

(i), (iii), (iv), (ii)

(iii), (i), (iv), (ii)

(iii), (i), (ii), (iv)

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Explanation

$R e a c t i v i t y α - I p o w e r$

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Which compound will form Schiff base with carbonyl compounds?

p-amines

sec-amines

bydroxylamine

Hydrazine

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Explanation

${C_{|}^{|}}_{R}^{R} = O + N H_{2} - R' \to {C_{|}^{|}}_{R}^{R} = N - R'$

N-alkyl or aryl imine is known as Schiff's base.

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