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Chemistry MCQs for NEET — Practice Questions with Answers

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Gem di-ether is obtained by:

(i) aldehyde, alcohol, $\overset{\oplus}{H}$

(ii) ketone, alcohol, $\overset{\oplus}{H}$

(iii) ketone, alcohol, O $\overset{\oplus}{H}$

(iv) aldehyde, alcohol, O $\overset{\oplus}{H}$

Select the correct answer from the codes given below:

Codes:

(i), (ii), (iii) and (iv)

(i), (ii) and (iv)

(iii) and (iv)

(i) and (ii)

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Explanation

Gem diether is acetal or ketal.

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Which among the following compounds will give addition reaction with water?

(i) $C H_{3} - C H = C H_{2}$

(ii) $C H_{3} - C \equiv C H$

(iii) $C C l_{3} - C H O$

(iv) $C H_{3} - C H O$

Select the correct answer from the codes given below:

Codes:

(i), (ii), (iii)

(i) and (ii)

(i), (ii), (iv)

only (iii)

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Explanation

Aduct of acetaldehyde is unstable.

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In the given reaction,

$C H_{3} - C \equiv N \overset{H_{2} O / ∆}{\to} (A) \overset{H_{2} O / \overset{\oplus}{H / ∆}}{\to} (B)$

(A) and (B) respectively are:

$O ∥ C H_{3} - C - N H_{2} a n d C H_{3} C O O H$

$C H_{3} C O O N H_{4} a n d C H_{3} C O O H$

$C H_{3} C O N H_{2} a n d C H_{3} C O O N H_{4}$

$C H_{3} - C H = N H a n d C H_{3} C O O H$

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Which among the following reagents can be used for the test of carbonyl group in laboratory?

$N H_{2} O H$

$N H_{2} N H_{2}$

$N a S O_{3} H$

$2, 4 - D N P H$

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In the reaction sequence,

$C_{6} H_{5} - C - C H_{3} \overset{N H_{2} O H / \overset{\oplus}{H}}{\to} (A) \overset{P_{2} O_{5}}{\to} [X] ∥ O$

[X] will be:

$C_{6} H_{5} - C - C H_{3} ∥ N - O H$

$C H_{3} C O O H$

$C_{6} H_{5} - N H_{2}$

$C H_{3} - C O - N H - C_{6} H_{5}$

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Consider the following statements for carbonyl compounds:

(i) They give nucleophilic addition reaction.

(ii) Aldehyde is more reactive than ketone for nucleophilic addition reaction.

(iii) $β -$ hydrogen of carbonyl compound is more acidic than $α -$ hydrogen.

(iv) They give addition reaction followed by elimination reaction with $N H_{2} - N H - C_{6} H_{4} - C H_{3}$ .

Of these statements:

(i) and (ii) are correct

(i), (ii) and (iv) are correct

(i), (ii) and (iii) are correct

(i), (ii), (iii) and (iv) are correct

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Explanation

$α - h y d r o g e n i s m o r e a c i d i c t h a n β - h y d r o g e n$

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Consider the following statements for a carbonyl compound:

(i) It gives addition reaction

(ii) It gives condensation reaction

(iii) It gives elimination reaction

(iv) It gives oxidation reaction

Of these statements:

(i), (ii), (iii) and (iv) are correct

(i) and (ii) are correct

(i), (ii) and (iii) are correct

(i), (ii) and (iv) are correct

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Explanation

its not an elimination reaction alone, its an addition reaction followed by elimination.

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Which one of the following pairs is correctly matched?

Saytzeff rule, least substituted alkene

Hofmann rule, most substituted alkene

E1cb reaction, Hofmann elimination

E1 reaction, Hofmann elimination

If both the assertion and the reason are true and the reason is a correct explanation of the assertion
If both the assertion and reason are true but the reason is not a correct explanation of the assertion
If the assertion is true but the reason is false
If both the assertion and reason are false

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Explanation

In E1cb reaction reaction intermediate is carbanion. Hence, product formation takes place according to Hofmann rule.

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Arrange the reactivity of alcohols in decreasing order for E1 elimination reaction:

(i) $O H l C H_{3} - C H - C H_{3}$

(ii) $O H l C H_{3} - C - C H_{3} l C H_{3}$

(iii) $O H l C_{6} H_{5} - C - C H_{3} l C H_{3}$

(iv) $C H_{3} - C H_{2} - C H_{2} O H$

Select the correct answer from the codes given below:

Codes:

(iii), (ii), (iv), (i)

(ii), (iii), (iv), (i)

(ii), (iii), (i), (iv)

(iii), (ii), (i), (iv)

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Explanation

Reactivity $α$ stability of carbocation

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In the given reaction,

$\overset{Br}{\overset{|}{{CH}_{2}}} - C H = C H_{2} \overset{N a N H_{2} / ∆}{\to} [X]$

[X] will be:

$C H_{3} - C \equiv C H$

$H_{2} C = C \equiv C H_{2}$

$C H_{3} - C \equiv \overset{⊝}{C} \overset{\oplus}{N} a$

$H_{2} C = C \equiv \overset{⊝}{C} H \overset{\oplus}{N} a$

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Explanation

$B r - C H_{2} - C H = C H_{2} \overset{\overset{⊝}{N} H_{2}}{\to} [C H_{2} = C = C H_{2}] \overset{R e a r r a n g e m e n t}{\to} [C H_{3} - C \equiv C H] \overset{N a N H_{2}}{\to} C H_{3} - C \equiv \overset{⊝}{C} \overset{\oplus}{N} a$

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