Practice free Alternating Current (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
In an ideal transformer, the turns ratio is $\dfrac{N_p}{N_s} = \dfrac{1}{2}$. The ratio $V_s : V_p$ is equal to (the symbols carry their usual meaning):
$V_s/V_p = N_s/N_p = 2:1$.
A 10 μF capacitor is connected to a 210 V, 50 Hz source as shown in figure. The peak current in the circuit is nearly ($\pi = 3.14$):
$X_C = 1/(\omega C) \approx 318.5\,\Omega$; $I_\text{peak} = \sqrt 2 \cdot 210/X_C \approx 0.93$ A.
To an ac power supply of 220 V at 50 Hz, a resistor of $20\ \Omega$, a capacitor of reactance $25\ \Omega$ and an inductor of reactance $45\ \Omega$ are connected in series. The corresponding current in the circuit and the phase angle between the current and the voltage is, respectively:
$Z = \sqrt{R^2+(X_L-X_C)^2} = \sqrt{20^2+20^2} = 20\sqrt2 \approx 28.3\ \Omega$. $I = \dfrac{220}{28.3} \approx 7.8$ A; $\tan\phi = \dfrac{20}{20} = 1\Rightarrow\phi = 45^\circ$.
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.