Electrostatics MCQs for NEET — Physics Questions with Answers

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An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be 

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Explanation

Kinetic energy K=12mv2=eV

v=2eVm

Two equal charges q of opposite sign separated by a distance 2a constitute an electric dipole of dipole moment p. If P is a point at a distance r from the centre of the dipole and the line joining the centre of the dipole to this point makes an angle θ with the axis of the dipole, then the potential at P is given by (r >> 2a) (Where p = 2qa

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A charge +q is fixed at each of the points x=x0,x=3x0,x=5x0 ..... infinite, on the x-axis and a charge –q is fixed at each of the points x=2x0,x=4x0,x=6x0,..... infinite. Here x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be Q4πε0r. Then, the potential at the origin due to the above system of charges is 

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Inside a hollow charged spherical conductor, the potential -

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Explanation

Inside the hollow sphere, at any point the potential is constant.

Two small spheres each carrying a charge q are placed r meter apart. If one of the spheres is taken around the other one in a circular path of radius r, the work done will be equal to 

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Explanation

The force is perpendicular to the displacement.

Two charged spheres of radii 10 cm and 15 cm are connected by a thin wire. No current will flow, if they have -

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Explanation

Because current flows from higher potential to lower potential.

The electric field inside a spherical shell of uniform surface charge density is -

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Explanation

All charge resides on the outer surface so that according to Gauss law, electric field inside a shell is zero.

The electric potential V at any point O (x, y, z all in metres) in space is given by V=4x2volt. The electric field at the point (1m,0,2m) in volt/metre is -

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Explanation

The electric potential V(x,y,z)=4x2volt

Now E=i^Vx+j^Vy+k^Vz

Now Vx=8x,Vy=0 and Vz=0

Hence E=8xi^, so at point (1m, 0, 2m)

E=8i^  volt/metre or 8 volt/metre along negative X-axis.

A hollow metal sphere of radius 5 cm is charged so that the potential on its surface is 10 V. The potential at the centre of the sphere is -

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Explanation

Since potential inside the hollow sphere is same as that on the surface.

If a unit positive charge is taken from one point to another over an equipotential surface, then -

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Explanation

On the equipotential surface, electric field is normal to the charged surface (where potential exists) so that no work will be done.

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