Practice free Magnetic Effects of Current and Magnetism (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Two small bar magnets are placed in a line with like poles facing each other at a certain distance d apart. If the length of each magnet is negligible as compared to d, the force between them will be inversely proportional to
A magnet of magnetic moment M is situated with its axis along the direction of a magnetic field of strength B. The work done in rotating it by an angle of 180o will be
A magnetic needle is kept in a non-uniform magnetic field. It experiences
(a)
In a non-uniform magnetic field, the force on each of the poles will be different in both magnitude and direction.
Due to difference in magnitude, the dipole experiences a force, Due to differences in direction, the dipole experiences a torque.
A long magnetic needle of length 2L, magnetic moment M and pole strength m units is broken into two pieces at the middle. The magnetic moment and pole strength of each piece will be
Two identical thin bar magnets each of length l and pole strength m are placed at the right angle to each other with the north pole of one touching south pole of the other. The magnetic moment of the system is :
When two identical bar magnets of length l and pole strength m are placed at right angles with their poles touching, their magnetic moments form a resultant at an angle of 45° to each magnet. The magnitude of the resultant magnetic moment is √2ml, as confirmed by the vector addition of the two equal magnetic moments ml.
Rate of change of torque with deflections maximum for a magnet suspended freely in a uniform magnetic field of induction B, when
A magnet of magnetic moment is placed along the x-axis in a magnetic field . The torque acting on the magnet is
The torque acting on a magnetic dipole moment (m) in a uniform magnetic field (B) is given by τ = m × B. Here, m = 50 Am^2 along x-axis and B = (0.5i + 3j) T. Taking the cross product, we get τ = (50)(3) = 150k N-m.
(d)
Two lines of force due to a bar magnet do not intersect at all.
A dip needle in a plane perpendicular to magnetic meridian will remain
(a) Dip needle can not rotate horizontally. When it is placed perpendicular to the magnetic meridian, it experiences a force due to vertical component of the earth's magnetic field only. SO it remains vertical.
If the angles of dip at two places are 30o and 45o respectively, then the ratio of horizontal components of earth's magnetic field at the two places will be
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