Blog Log in Get Started Free

Measurement MCQs for NEET — Physics Questions with Answers

Practice free Measurement (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology

Language English हिंदी

Chapter Difficulty Show only questions I answered incorrectly Clear Register free for difficulty & keyword filters

● ● ● ● ●

The dimensions of emf in MKS is

$M L^{- 1} T^{- 2} Q^{- 2}$

$M L^{2} T^{- 2} Q^{- 2}$

$M L T^{- 2} Q^{- 1}$

$M L^{2} T^{- 2} Q^{- 1}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$V = \frac{W o r k}{C h a r g e} [V] = \frac{M L^{2} T^{- 2}}{Q} = M L^{2} Q^{- 1} T^{- 2}$

● ● ● ● ●

Which of the following quantities is dimensionless

Gravitational constant

Planck's constant

Power of a convex lens

None

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$[G] = [M^{- 1} L^{3} T^{- 2}]; [h] = [M L^{2} T^{- 1}]$

Power = $\frac{1}{focal length} = [L^{- 1}]$

All quantities have dimensions

● ● ● ● ●

The dimensional formula for Boltzmann's constant is

$[M L^{2} T^{- 2} θ^{- 1}]$

$[M L^{2} T^{- 2}]$

$[M L^{0} T^{- 2} θ^{- 1}]$

$[M L^{- 2} T^{- 1} θ^{- 1}]$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$k = [\frac{R}{N}] = [M L^{2} T^{- 2} θ^{- 1}]$

● ● ● ● ●

The dimensions of K in the equation $W = \frac{1}{2} K x^{2}$ is

$M^{1} L^{0} T^{- 2}$

$M^{0} L^{1} T^{- 1}$

$M^{1} L^{1} T^{- 2}$

$M^{1} L^{0} T^{- 1}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$W = \frac{1}{2} k x^{2} \Rightarrow [k] = \frac{[W]}{[x^{2}]} = [\frac{M L^{2} T^{- 2}}{L^{2}}] = [M T^{- 2}]$

● ● ● ● ●

The physical quantities not having same dimensions are

Speed and ${(μ_{0} ε_{0})}^{- 1 / 2}$

Torque and work

Momentum and Planck's constant

Stress and Young's modules

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Momentum $[M L T^{- 1}]$ , Planck's constant $[M L^{2} T^{- 1}]$

● ● ● ● ●

Dimension of R is

$M L^{2} T^{- 1}$

$M L^{2} T^{- 3} A^{- 2}$

$M L^{- 1} T^{- 2}$

None of these

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$R = \frac{V}{I}$ $= [\frac{M L^{2} T^{- 3} A^{- 1}}{A}]$ = $[M L^{2} T^{- 3} A^{- 2}]$

● ● ● ● ●

The dimensional formula of relative density is

ML^–3

LT^–1

MLT^–2

Dimensionless

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Relative density = $\frac{Density of substance}{density of water}$ $= [M^{0} L^{0} T^{0}]$

● ● ● ● ●

The dimensional formula for young's modulus is

$M L^{- 1} T^{- 2}$

$M^{0} L T^{- 2}$

MLT^–2

$M L^{2} T^{- 2}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$M L^{- 1} T^{- 2}$

● ● ● ● ●

Frequency is the function of density $(ρ)$ , length (a) and surface tension (T). Then its value is

$\frac{\sqrt{T}}{{kρ}^{1 / 2} a^{3 / 2}}$

$k ρ^{3 / 2} a^{3 / 2} / \sqrt{T}$

$\frac{T^{3 / 2}}{{kρ}^{1 / 2} a^{3 / 2}}$

$\frac{T^{3 / 2}}{{kρ}^{1 / 2} a^{1 / 2}}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$n = {kp}^{a} a^{b} T^{c} [M^{0} L^{0} T^{- 1}] = {[{ML}^{- 3}]}^{a} {[L]}^{b} {[{MT}^{- 2}]}^{c} [M^{0} L^{0} T^{- 1}] = [M^{a + c} . L^{- 3 a + b} . T^{- 2 c}] \Rightarrow a + c = 0 . . . . . (i) - 3 a + b = 0 . . . . . (ii) - 2 c = - 1 \Rightarrow c = \frac{1}{2} a = - \frac{1}{2} b = - \frac{3}{2} n = k . \frac{\sqrt{T}}{\sqrt{p} . a^{\frac{3}{2}}}$

● ● ● ● ●

The dimensions of electric potential are

$[M L^{2} T^{- 2} Q^{- 1}]$

$[M L T^{- 2} Q^{- 1}]$

$[M L^{2} T^{- 1} Q]$

$[M L^{2} T^{- 2} Q]$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$V = \frac{W}{Q} = [M L^{2} T^{- 2} Q^{- 1}]$

Ready to ace NEET?

Free access · No credit card required

Browse All Questions Create Free Account

Frequently Asked Questions

Yes. You can attempt every Measurement question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.