Practice free Measurement (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
A physical quantity x is given by $ x = { A^4 B^{1 \over 4 } \over C^3 D^{4 \over 3 }} $ due to which physical quantity produced the maximum percentage error in x
The resistance $ R = { V \over I } $ where $ V = 100 \pm 5 volts $ and $ I = 10 \pm 0.3 amperes $ calculate the percentage error in R.
$$ Resistance R = { V \over I} $$ ${ \triangle R \over R } = { \triangle V \over V } + { \triangle I \over I } $ $ { \triangle R \over R } = { 5 \over 100} + { 0.3 \over 10 } $ $ { \triangle R \over R } = { 8 \over 100} $ $ { \triangle R \over R } \% = 8 \% $
The number of significant figures in 0.000150 is ...............
In the number 0.000150, the significant figures are the digits that carry meaning contributing to its measurement resolution. Leading zeros are not counted as significant. Hence, the significant figures are '1', '5', and '0', which total to 3 significant figures.
Which of the following numerical value have significant figure 4 ?
A number has four significant figures if it has four digits that contribute to its precision. In the number 1.011, all four digits ('1', '0', '1', '1') are significant as they contribute to the precision of the number.
What is the number of significant figures in $ 5.50 \times 10 ^ 3 $ ?
In the number $5.50 imes 10^3$, the significant figures are determined by the digits in the coefficient (5.50 in this case), not the exponent. The digits '5', '5', and '0' are all significant, making a total of 3 significant figures.
The significant figures in 500.5000 are ...............
The number 500.5000 has 7 significant figures. All the digits including the trailing zeros after the decimal point are considered significant.
Addition of measurement 15.225 cm, 7.21 cm and 3.0 cm in significant figure is ...............
When adding numbers, the result should be reported with the same number of decimal places as the number with the least decimal places. Here, 15.225 cm (3 decimal places), 7.21 cm (2 decimal places), and 3.0 cm (1 decimal place) are added. Therefore, the result should have 1 decimal place: 15.225 + 7.21 + 3.0 = 25.435 cm, which rounds to 25.4 cm.
Subtract 0.2 J from 7.36 J and express the result with correct number of significant figures.
After rounding of the number 9595 to 3 significant digits the value becomes ...............
How many significant numbers are there in $ (2.30 + 4.70) \times 10^ 5 $ ?
When performing operations with significant figures, the result should have the same number of significant figures as the value with the least number of significant figures. In the expression $(2.30 + 4.70) imes 10^5$, both 2.30 and 4.70 have 3 significant figures. The sum is 7.00, which also has 3 significant figures. Therefore, the number of significant figures in the result is 3.
Ready to ace NEET?
Free access · No credit card required
Yes. You can attempt every Measurement question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.
No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.
The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.